Loses electron as negative charge is lost therefore becomes overall positive.
The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.
<h3>How to solve for the time interval</h3>
We have y = 0.175
y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175
sin (1.25x + 99.6t) = 0.175
sin (1.25x + 99.6t) = 0.5
99.62 = pi/6
t1 = 5.257 x 10⁻³
99.6t = pi/6 + 2pi
= 0.0683
The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.
b. we have k = 1.25, w = 99.6t
v = w/k
99.6/1.25 = 79.68
s = vt
= 79.68 * 0.0683
= 5.02
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complete question
A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?
The correct answer is
<span>b. increases with the square of speed
In fact, the kinetic energy of a moving object is given by
</span>
<span>where m is the mass of the object and v is its speed. We see that the kinetic energy is directly proportional to the square of the speed, therefore option B is the correct one.</span>
Answer: 9.8N
Explanation: The velocity of a sound wave (v), tension on the string (T) and mass per unit length (u) are all related by the formulae below
T = v² * u
Where T is tension in Newton (N), v is velocity of sound waves in meter per seconds (m/s) and u is mass per unit length in kilogram per meter (kg/m)
u = mass of chord / length of chord
u = 0.44/ 8.1
u = 0.1 kg/m
Velocity of sound waves (v) =length of chord / time taken for wave to travel
v = 8.1 / 0.82 = 9.9m/s
Tension is calculated below using the formula
T = v² * u
T = (9.9)² x 0.1
T= 9.8N
