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Sonja [21]
3 years ago
8

Please help me with these factoring problems. Please help me solve. I can't do these!!

Mathematics
1 answer:
aleksley [76]3 years ago
3 0
Simple...

you have: 

1.) -8x-16  --->>>

Factor out a -8 -->>

-8(x+2)

2.)9d+15db --->

Factor out 3d -->

3d(3+5b)

3.) 2a-9ax-->>

Factor out -a -->

-1a(9x-2)

Thus, your answer.
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What is the distance between each pair of numbers?
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Working alone, Henry takes 3 hours less than Mary to clean the carpets in the entire office. Working together, they can clean th
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Answer:

It would take Henry 3 hours to clean the office carpets if Mary were not there to help

Step-by-step explanation:

Assume that it takes Henry t hours to clean the carpets

∵ Henry takes 3 hours less than Mary to clean the carpets

∵ Henry takes t hours

- That means add 3 to t to find Mary time

∴ Mary takes t + 3 hours

∵ The rate of Henry is \frac{1}{t}

∵ The rate of Mary is \frac{1}{t+3}

∵ Working together, they can clean the carpets in 2 hours

- Add the two rates and equate the answer by \frac{1}{2} (their rate together)

∴ \frac{1}{t}+\frac{1}{t+3}=\frac{1}{2}

Multiply the two denominators and multiply each numerator by the other denominator to add the two fractions of the left hand side

∵ \frac{(1)(t+3)}{t(t+3)}+\frac{(1)t}{t(t+3)}=\frac{1}{2}

∴  \frac{(t+3)}{t(t+3)}+\frac{t}{t(t+3)}=\frac{1}{2}

- Add the two fractions in the left hand side

∴ \frac{t+3+t}{t(t+3)}=\frac{1}{2}

∴  \frac{2t+3}{t^{2}+3t}=\frac{1}{2}

Use the cross multiplication

∵ (t² + 3t)(1) = 2(2t + 3)

∴ t² + 3t = 4t + 6

- Subtract 4t from both sides

∴ t² - t = 6

- Subtract 6 from both sides

∴ t² - t - 6 = 0

- Factorize it into two factors

∴ (t - 3)(t + 2) = 0

Equate each factor by 0 to find t

∵ t - 3 = 0

- Add 3 to both sides

∴ t = 3

OR

∵ t + 2 = 0

- Subtract 2 from both sides

∴ t = -2 ⇒ reject this answer because there is no - ve time

∴ t = 3

∴ Henry would take 3 hours to clean the carpets alone

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