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3 years ago

Please help me with these factoring problems. Please help me solve. I can't do these!!

1 answer:

3 0

Simple...

you have:

1.) -8x-16 --->>>

Factor out a -8 -->>

-8(x+2)

2.)9d+15db --->

Factor out 3d -->

3d(3+5b)

3.) 2a-9ax-->>

Factor out -a -->

-1a(9x-2)

Thus, your answer.

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Please find the answer

kati45 [8]

Y is 45 and X is 70.

8 0

3 years ago

Read 2 more answers

Help please help me please

STatiana [176]

(x , y → (x - 5, y - 3)

the coordinates of S(1 , 5),T(1,1), U(4, 1)

the coordinates of the image are S'( - 4, 2), T'( - 4, - 2), U'( - 1 , - 2)

consider the difference in the x- coordinates of the original to the image

1 → - 4 = - 5, 1 → - 4 = - 5, 4 → - 1 = - 5

so the x- coordinate rule is x - 5

now consider the difference in the y- coordinates of the original to the image.

5 → 2 = - 3, 1 → - 2 = - 3, 1 → - 2 = -3

so the y- coordinate rule is y - 3

hence (x, y) → (x - 5, y - 3)

6 0

4 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP(25 points)

miskamm [114]

Answer: I hope it helps :)

x=6 , y=6√3
x =23√3 , y=23
u =12 , v= 6
a =18√2 , b =18
x = 13 , y= 13

Step-by-step explanation:

$Hypotenuse =x\\Opposite =y \\Adjacent =6\\\alpha = 6\\Let's\: find\: the \:hypotenuse\: first\\Using SOHCAHTOA\\Cos \alpha = \frac{adj}{hyp} \\Cos 60 = \frac{6}{x} \\\frac{1}{2} =\frac{6}{x} \\Cross\:Multiply\\x = 12\\Let's\: find\: y\\Hyp^2=opp^2+adj^2\\12^2=y^2+6^2\\144=y^2+36\\144-36=y^2\\108=y^2\\\sqrt{108} =\sqrt{y^2} \\y=6\sqrt{3}$

$Opposite =x\\Hypotenuse = 46\\Adjacent =y \\\alpha =60\\Using \: SOHCAHTOA\\Sin \alpha =\frac{opp}{adj} \\Sin 60=\frac{x}{46}\\\\\frac{\sqrt{3} }{2} =\frac{x}{46} \\2x=46\sqrt{3} \\x = \frac{46\sqrt{3} }{2} \\x =23\sqrt{3} \\\\Hyp^2=opp^2+adj^2\\46^2=(23\sqrt{3} )^2+y^2\\2116=1587+y^2\\2116-1587=y^2\\529=y^2\\\sqrt{529} =\sqrt{y^2} \\y = 23$

$Hypotenuse = u\\Opposite =6\sqrt{3} \\Adjacent = v\\\alpha =60\\Sin\: 60 = \frac{6\sqrt{3} }{u} \\\frac{\sqrt{3} }{2} =\frac{6\sqrt{3} }{u} \\12\sqrt{3} =u\sqrt{3} \\\\\frac{12\sqrt{3} }{\sqrt{3} } =\frac{u\sqrt{3} }{\sqrt{3} } \\u = 12\\Hyp^2=opp^2+adj^2\\12^2= (6\sqrt{3} )^2+v^2\\144=108+v^2\\144-108=v^2\\36 = v^2\\\sqrt{36} =\sqrt{v^2} \\\\v =6$

$Hypotenuse = a\\Opposite =18 \\Adjacent = b\\\alpha =45\\Tan \alpha = opp/adj\\Tan \:45 =18/b\\1=\frac{18}{b}\\ b = 18\\\\Hyp^2=Opp^2+Adj^2\\a^2 = 18^2+18^2\\a^2=324+324\\a^2=648\\\sqrt{hyp^2} =\sqrt{648}\\ \\a =18\sqrt{2}$

$Hypotenuse = 13\sqrt{2}\\ Opposite =x\\Adjacent = y\\\alpha =45\\Sin\:\alpha = opp/hyp\\Sin 45=x/13\sqrt{2}\\ \\\frac{\sqrt{2} }{2} =\frac{x}{13\sqrt{2} } \\2x=26\\2x/2=26/2\\\\x = 13\\\\Hyp^2=opp^2+adj^2\\(13\sqrt{2})^2=13^2+y^2\\ 338=169+y^2\\338-169=y^2\\169=y^2\\\sqrt{169} =\sqrt{y^2} \\13 = y$

7 0

3 years ago

I need help solving these

lawyer [7]

All of them are involved with variables. :)

5 0

3 years ago

Write a word problem that can be solved by multiplying a whole number and a fraction. Include the solution.

adelina 88 [10]

Answer:

Sheila had 24 cupcakes, she gave 1/3 of them to Caleb. How many cupcakes did she give to Caleb?

Step-by-step explanation:

24 x 1/3 = 8

She gave 8 cupcakes to Caleb.

8 0

2 years ago