It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
The answer is letter choice B
A = pi * r^2
<span>A = 3.14 * 50^2 </span>
<span>A = 7,850 square miles (area of the 50 mile broadcast signal)
A = pi * r^2
A = 3.14 * 75^2
A = </span>17,662.5 = 17,663 square miles (area of the 75 mile relayed signal)
Now we just need to subtract the 50 mile signal from the 75 mile signal, so:
17,663 - 7,850 = <span>9,813 square miles greater
Hope this helps :)
</span>
Down on the bottom, under the fraction line.
Answer:
14 students walk
Step-by-step explanation:
40 total
22 girls
18 boys - 7 boys who cycle = 11 boys - 6 who take the bus. That leaves 5 boys who walk.
9 girls walk
5 + 9 = 14 total.
