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GarryVolchara [31]
3 years ago
12

Send help please!! i want to complete it asap

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0
It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6

So 4.2 (median) will lie in that interval 60-70 years.
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a line goes through the point(6,-2)and has a slope of -3 what is the value of a if the point (a,7) lies on the line​
yaroslaw [1]

Answer:

The value of a is "3", to complete the coordinate point (3,7) on the line.

Step-by-step explanation:

We are given the slope of the line, and also one point through which the line passes. Therefore, we can find the actual equation of the line by using the slope-point form of the line:

y-y_0=m(x-x_0)\\y-(-2)=(-3)(x-6)\\y+2=-3x+18\\y=-3x+18-2\\y=-3x+16

Now, we need to find which value of "x" renders a y-value of "7", to complete the coordinate pair (a, 7) as requested. Therefore, we ask for the y-value in the previous equation to be "7", and solve for its associated x-value:

y=-3x+16\\7=-3x+16\\7-16=-3x\\-9=-3x\\x=\frac{-9}{-3} \\x=3

Therefore, x = 3

3 0
3 years ago
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Two ships leave a harbor at the same time. One ship travels on a bearing Upper S 14 degrees Upper W at 15 miles per hour. The ot
jekas [21]

Answer:

69.94 miles

Step-by-step explanation:

The distance d₁ the first ship moves after 3 hours is 3 hours × 15 miles per hours = 45 miles

The distance d₂ the second ship moves after 3 hours is 3 hours × 12 miles per hours = 36 miles.

The angle the first ship's direction makes in the North-East direction is 90° - 75° = 15°

The angle the second ship's direction makes in the South-West direction  = 14°

The distance moved by the two ships form the side of a triangle. The angle,  θ between the two ship directions is 14° + 90° + 15° = 119°

Using the cosine rule, we find the distance d between the two ships

d = √(d₁² + d₂² -2d₁d₂cosθ)

= √(45² + 36² -2×45×36cos119°)

= √(2025 + 1296- (-1570.78))

= √(3321 + 1570.78)

= √4891.78

= 69.94 miles

4 0
3 years ago
Worth a lot of points!
Alla [95]

Answer:

15a² + 21a + 19 = 0

Step-by-step explanation:

Given

(4a + 3)² = (a + 5)(a - 2)

(4a + 3)(4a + 3) = (a + 5)(a - 2 ) ← expand both sides using FOIL

16a² + 24a + 9 = a² + 3a - 10 ( subtract a² + 3a - 10 from both sides )

16a² - a² + 24a - 3a + 9 + 10 = 0 ← collect like terms

15a² + 21a + 19 = 0

8 0
3 years ago
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