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3 years ago

15

-5x=-6 what is the value of x?

2 answers:

Nataly_w [17]3 years ago

7 0

Answer:

6/5

Step-by-step explanation:

fiasKO [112]3 years ago

4 0

Answer: x=6/5

Step-by-step explanation:

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Which of the following equations represents the graph shown?

Elina [12.6K]

Answer:

ok from looking at this equation we can we that every it goes 1 up and on over so

-x+2

Hope This Helps!!!

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2 years ago

Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndR

katen-ka-za [31]

Answer: B. 2 = 3x + 10x2

Step-by-step explanation:

This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:

[-3+-sqrt(3^2+4(10)(2))]/(2(10))

The formual that was applied here was a quadratic formula given by:

x=[-b+\-sqrt(b^2-4ac)]/2a

whereby from the our substituted values above,

a=10,b=3 and c=-2

such that the quadratic equation will be:

10x^2+3x-2

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3 years ago

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Fracciones equivalente 1/4

stealth61 [152]

2/4 esa es una ojalá y pude contestar a tiempo

6 0

3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

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3 years ago

There are 45 boys and 60 girls in Year 6. What is the ratio of boys to girls? Write the ratio in the simplest form

exis [7]

The answer to this is 3:4

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3 years ago

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