The random variable X is normally distributed. P(2045).
1 answer:
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Answer:
The coordinates of J are missing. Plus, I don't see options for the conclusions. I made an imaginary point J, which you could correct to form the proper triangle.
Step-by-step explanation:
See the attachment. Plot all the vertices, including a corrected point J and draw the resulting triangle. It might be that AJKL is a slightly smaller, shifted version of AGHI. Enter the correct coordinates and then compare.
Answer:
Distance covered by the bird before meeting the water is: 51.264 ft
Step-by-step explanation:
Notice that if the bird catches the fish in 2 seconds, then the fish was able to dive down a total of 6 feet before being caught:
So the bird needs to fly in the direction of the hypotenuse of a right angle triangle (see attached image) that has one leg of length (24 ft + 6 ft) = 30 ft, and another one 22.5 ft (half the width of the river.
Such hypotenuse is (using Pythagoras theorem):
Now, in order to find the distance D the bird covers from the top of the tree to the water (marked in red in our image), we use similar triangles. The bigger triangle is that of legs 60 ft and 22.5 ft and hypotenuse 64.08 ft.
The smallest triangle we use in the proportion is the one shaded yellow in the image, which has one leg equal to 24 ft, and unknown hypotenuse:
So we make the proportion between known legs, and hypotenuses:
