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love history [14]
3 years ago
6

The random variable X is normally distributed. P(2045).

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0
What the answer option
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A furniture company manufactures desks and chairs. Each desk uses four units of wood, and each chair uses three units of wood. A
Pavlova-9 [17]

Answer:

$180000

Step-by-step explanation:

Let's c be the number of chair and d be the number of desks.

The constraint functions:

- Unit of wood available 4d + 3c <= 2000 or d <= 500 - 0.75c

- Number of chairs being at least twice of desks c >= 2d or d <= 0.5c

c >= 0

d >= 0

The objective function is to maximize the profit function

P (c,d) = 400d + 250c

We draw the 2 constraint functions (500 - 0.75c and 0.5c) on a c-d coordinates (witch c being the horizontal axis and d being the vertical axis)  and find the intersection point 0.5c = 500 - 0.75c

1.25c = 500

c = 400 and d = 0.5c = 200 so P(400, 200) = $250*400 + $400*200 = $180,000

The 500 - 0.75c intersect with c-axis at d = 0 and c = 500 / 0.75 = 666 and P(666,0) = 666*250 = $166,500

So based on the available zones in the chart we can conclude that the maximum profit we can get is $180000

7 0
4 years ago
Hi, please help
SOVA2 [1]

Answer:

A. 133 degrees

Step-by-step explanation:

You add the two known interior numbers in the triangle to find the unknown exterior variable. In this case, the two known interior numbers are 83 and 50. 83 + 50 = 133

7 0
3 years ago
What's the answer???
mafiozo [28]
I believe it is A. hope this helps
5 0
4 years ago
The time (in minutes) taken for a dose of a certain drug to be effective as a sedative on lab animals is normally distributed wi
Anni [7]

Answer:

Step-by-step explanation:

Let x be the random variable representing the time (in minutes) taken for a dose of a certain drug to be effective as a sedative on lab animals. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 1

σ = √variance = √0.01 = 0.1

the probability that the time taken for a randomly selected animal is between 1 and 1.1 minutes is expressed as

P(1 ≤ x ≤ 1.1)

For x = 1,

z = (1 - 1)/0.1 = 0

Looking at the normal distribution table, the probability corresponding to the z score is 0.5

For x = 1.1

z = (1.1 - 1)/0.1 = 1

Looking at the normal distribution table, the probability corresponding to the z score is 0.84

Therefore,

P(1 ≤ x ≤ 1.1) = 0.84 - 0.5 = 0.34

The the proportion of animals for which the time taken is between 1 and 1.1 minutes is 0.34

8 0
3 years ago
Question 3 (1 point)
anzhelika [568]

Answer:

toothburhses

Step-by-step explanation:

4 0
3 years ago
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