No work needed just answers also no need to to all of them but please do at least one of them.

I NEED help pleaseee

dangina [55]

5 to the fifth power or 3125

8 0

3 years ago

Read 2 more answers

Find all the critical points of h(x) = x^3 − 3x^4 and categorize them as local

neonofarm [45]

Answer:

0 is an inflection point

1/4 is a local maximum.

Step-by-step explanation:

To begin with you find the first derivative of the function and get that

$h'(x) = 3x^2 - 12x^3$

to find the critical points you equal the first derivative to 0 and get that

$3x^2 - 12x^3 = 0, x = 0,1/4$

To find if they are maximums or local minimums you use the second derivative.

$h''(x) = 6x-36x^2$

since $h''(0) = 0$ is neither an inflection point, and since $h''(1/4) = -3/4$ then 1/4 is a maximum.

6 0

3 years ago

Which of the ordered pairs in the form (x, y) is a solution of this equation?

Tju [1.3M]

Answer:

Both ordered pairs are solutions to this equation.

Step-by-step explanation:

If you plug in the x and y values given in the ordered pair, you make the left side of the equation equal the right for both pairs.

6 0

3 years ago

Sara jumps off a diving board that is 6 feet above the surface of the water her height above the surface of the water h in feet

Flauer [41]

Well when she hits the water h=0 so

2t^2-t-6=0 factor

2t^2-4t+3t-6=0

2t(t-2)+3(t-2)=0

(2t+3)(t-2)=0, since t>0

t=2 seconds...

However it should be noted that h(t)=-2t^2+t+6 implies that

v(t)=dh/dt=-4t+1 and

a(t)=dv/dt=-4

Since this is a free fall equation, this would suggest that the acceleration due to gravity is -4, whether that is supposed to be -4ft/s^2 or -4m/s^2, it certainly is not on this planet! :D If it is -4ft/s^2 it could be on the Moon or if it is -4m/s^2 it could be on Mars.

7 0

3 years ago

1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti

uysha [10]

Answer:

1) $0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

b) $ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=0.0826052$ represent the sample mean

$\mu$ population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size

Part 1

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=5-1=4$

The Confidence level is 0.95 or 95%, and the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ , the critical value would be using the t distribution with 4 degrees of freedom: $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

Part 2

The original margin of error is given by:

$ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

3 0

3 years ago