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Ipatiy [6.2K]
3 years ago
14

A company manufactures printers.

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

get x isolated

Step-by-step explanation:

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Maria washes the windows in her house every 2 tweaks, meows her lawn every 3 weeks, and trims her garden bushes every 5 weeks. T
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In another 30 weeks, because 2x3x5=30 weeks where she does all of the activities.<span />
4 0
3 years ago
david quiere saber cuanto requiere invertir mensualmente para obtener $30,760.08 durante 6 meses si los invierte con el 12% capi
Akimi4 [234]

Answer:

A = $32,652.44

Step-by-step explanation:

Given: Principal (P) = 30,760.08, Annual Rate (R) = 12%, Time (t in years) = 0.5

To find: How much David needs to invest monthly

Formula: A = P(1 + r/n)^n^t

Solution: To find, simply add principal + interest

First, convert R as a percent to r as a decimal

r = R/100

r = 12/100

r = 0.12 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 30,760.08(1 + 0.12/12)(12)(0.5)

A = 30,760.08(1 + 0.01)(6)

A = $32,652.44

Therefore;  

The total amount David will obtain with 30,760.08 for 6 months, 12%is $32,652.44.

4 0
3 years ago
Itskorey please help me im stuck again<br><br> one hundred seventy thousands
vlada-n [284]
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Which equation represents the data shown in the table below
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2 years ago
Read 2 more answers
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


We subtract equation (2) from equation (1) to get,


11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


This implies that,


6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



We divide both sides by 3 to get,


d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
7 0
3 years ago
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