In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
-10v^9+8v^6+2v^5
10=5*2
8=2^3
2=2
The common factor is 2 and its least exponent is 1
The least exponent for the variable v is 5
Then, the GFC of the polynomial is 2v^5
Factoring:
2v^5 [ -(10v^9)/(2v^5)+(8v^6)/(2v^5)+(2v^5)/(2v^5) ] =
2v^5 (-5v^(9-5)+4v^(6-5)+1) =
2v^5 (-5v^4+4v+1)
Answer:
103/28
Step-by-step explanation:
Let the number be 'x'
Equation:-
7x - 3/4 = 25
7x = 25 + 3/4
7x = 100/4 + 3/4
7x = 103/4
x = 103/(4 x 7)
x = 103/28
Answer:
B
Step-by-step explanation: