Three cube-shaped boxes are stacked one above the other. The volumes of two of the boxes are 729 cubic meters each, and the volu
1 answer:
You might be interested in
To solve this, we will first use order of operations to multiply the terms inside the parentheses, multiply the product by the term outside of the parentheses, and then add from left to right.
5.6 * 2 = 11.2
11.2 * 4.5 = 50.4
50.4 + 1.2 = 51.6
Therefore, 51.6 is the solution.
Answer:
The original price range of soda is $10 to $39.4
Step-by-step explanation:
Given as :
The discount coupon applied on grocery = 5%
The cost of soda after discount coupon ranges = $0.50 to $1.97
Let the original price range of soda = $A
Now, According to question
discount on original price = the cost after discount
So, initial original price = x
5% of x = $0.50
0.05 × x = $0.50
∴ x =
i.e x = $10
Again final original price = y
5% of y = $1.97
0.05 × y = $1.97
∴ y =
i.e y = $39.4
So, The original price range of soda = $A = $10 to $39.4
Hence, The original price range of soda is $10 to $39.4 Answer
Split up the interval [2, 5] into 
equally spaced subintervals, then consider the value of 
at the right endpoint of each subinterval.
The length of the interval is
, so the length of each subinterval would be 
. This means the first rectangle's height would be taken to be 
when 
, so that the height is 
, and its base would have length 
. So the area under over the first subinterval is 
.
Continuing in this fashion, the area under over the 
th subinterval is approximated by 
, and so the Riemann approximation to the definite integral is
and its value is given exactly by taking
. So the answer is D (and the value of the integral is exactly 39).
The length of the interval is
Continuing in this fashion, the area under
and its value is given exactly by taking