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RSB [31]
3 years ago
11

Sophia has fabric to make banners for school she needs 1 and 1/4 yards of fabric for each Banner she has made 4 banners and has

2 and a 1/2 yards of fabric left over how much fabric did she begin with ​
Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0

Answer: 7 and a 1/2

Step-by-step explanation: 1 and 1/4 times4 = 5 plus 2 and a 1/2 = 7 and a 1/2

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Answer Please Please <br> I need answe fast
Svet_ta [14]

Answer:

78.4

Step-by-step explanation:

8 0
2 years ago
Solve.<br> 3(5z + 7) = 33
Ivenika [448]

Answer:

z = 4/5

Step-by-step explanation:

3(5z + 7) = 33

Divide each side by 3

3/3(5z + 7) = 33/3

5z+7 = 11

Subtract 7 from each side

5z+7-7 = 11-7

5z = 4

Divide by 5

5z/5 = 4/5

z = 4/5

3 0
3 years ago
Read 2 more answers
Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave
Colt1911 [192]
Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \  \frac{a-\mu}{\sigma}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\  \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\  \\ =1-P(z\ \textless \ -0.5410) \\  \\ =1-0.29426=\bold{0.7057}



Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span>P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}
7 0
3 years ago
Solve the equation. Round to the nearest tenth if necessary.
ASHA 777 [7]
The answer will be 30
5 0
3 years ago
Help on Number 8? I know Y=5 and the slope is undefined and x=2 but I don’t know what to do now.
Stels [109]

To find the slope, use the equation of a line: y = mx + b

Plug in the values for x and y:

5 = 2x + b

We know that 2 can fit into 5 twice, which means 2*2 is 4.

We now have 5 = 4 + b.

If 5 is b more than 4, then this means that 4 is b less than 5. Subtract 4 from both sides, and you will have b = 1.

This means your equation is y = 2x + 1.

3 0
3 years ago
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