Write each equation in standard form. y=0.5x+3

A store sells four-packs of permanent markers in assorted colors for $3.19 per pack. All spiral-bound notebooks, whether wide-ru

Gekata [30.6K]

Answer: (x3.19+y1.20 + z1.20) x 1.06

Step-by-step explanation:

Hi, to answer this question we have to write an expression.

Four-packs of permanent markers in assorted colors for $3.19 per pack.

3.19 x (x number of packs purchased)

spiral-bound notebooks, whether wide-ruled or college-ruled, sell for $1.20 each

1.20 y + 1.20 z (y wide-ruled notebooks, and z college-ruled notebooks)

The store charges a 6% sales tax on Cleo’s total bill, so we have to multiply the expression by 1+ 0.06 ( 1+ tax percentage in decimal form)

(x3.19+y1.20 + z1.20) x 1.06

8 0

3 years ago

Which of the following does not name the same line? MN KM KN KL

garik1379 [7]

Answer:

KL does not name the same line.

Step-by-step explanation:

You'll recognize that if you go from KM, it stays on the same. You go from MN it stays on the same line. KN also stays on the same line. By K and L are two completely different lines. L can only be with N or J

8 0

3 years ago

Please help!! Will mark first answerer brainiest!! Thank you so much!!

geniusboy [140]

C. Is the answer to this question

8 0

3 years ago

What is the simplified form of the following expression?

Igoryamba

Answer:

169 is the answer.

Step-by-step explanation:

I used a calculator.

7 0

3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago