4. In cell-B8, create a formula without using a function that multiplies the value.in.cell.B7. by the value-in-cell-B6-andthen adds-the-value in B7..Update.the-cell-reference to cell: B6, from a relative reference to a mixed-reference by making an absolute-reference to row.6..Copy-the-formula-from-cell-B8-to-the-range-B9:B11-and-then-copy-the-formulas. from the range-B8:B11-to-the-range-C8:H11.1 13. SALO extend the list of years to the range A15:A17.1 In-cell-B13, create-a formula without a function using absolute references that subtracts the values of cells.B5 and B7.from.cell-B6 and then multiplies the result.by.cell-B8. Copy the formula-from-cell-B13 to the range C13:H13.1 In-cell-B14, create-a formula without using a function that adds.1.to the value-in-cell B12 and then multiplies the result by the value-in-cell-B13Update-the-referenceto-cell B12, from a relative-reference to a mixed-reference by making an absolute reference to row.12. Copy the formula-from-cell-B14-to-the-range-B15:B17 and then copy the formulas.from-the-range-B14:B17 to the range-C14H17.1
Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Answer:
a¹⁸b²⁴c⁵⁴
Step-by-step explanation:
(aᵇ)ᶜ = aᵇᶜ = aᵇ×ᶜ
(-aⁿ)ᵒᵈᵈ = -aⁿ
(-aⁿ)ᵉᵛᵉⁿ = aⁿ
aⁿ × aⁿ = aⁿ⁺ⁿ
_________
In this situation, 6 is an even exponent which means that the negative coefficient of this 9th degree monomial will be positive. Now the only step is to multiply the exponents by the exponent outside of the perenthesis which is 6.
so (-a³b⁴c⁹)⁶ = ((-a³)⁶(b⁴)⁶(c⁹)⁶) = ((a³ˣ⁶)(b⁴ˣ⁶)(c⁹ˣ⁶)) = ((a¹⁸)(b²⁴)(c⁵⁴)) = <em>a¹⁸b²⁴c⁵⁴</em>
Answer:
131.04
Step-by-step explanation:
0.7×180=126
1.04×126=131.04
