First, we have to make one of the x's have the same coefficient so they can cancel each other out (or eliminate)
3(x+y) = 3(2)
you're going to have to do it to both sides to keep it balanced
3x+3y=6
now line them up and add them
3x+3y= 6
+ (-3x+4y=15)
since the 3x and -3x add up to 0x and cancels each other, you're left with
7y = 21
divide both sides by 7
y=3
plug in the y into one of the original equations
x+y=2
x + 3 = 2
subtract 3 from both sides
x = -1
x = -1 , y = 3
Answer:
true!
Step-by-step explanation:
wait bang like fight
or bang like you know f u c k
btw mark brainliest plz
Well, if you divide 162 by 18 you get 9 so,
The answer is 9
The equation of the line segment through A and B is given as
-7x + 3y = -21.5
In standard form,
3y = 7x - 21.5
y = (7/3)x - 7.1667
Line AB has a slope of 7/3.
Let the equation of line segment PQ be
y = mx + b
Because line segments AB and PQ are perpendicular, therefore
(7/3)*m = -1
m = -3/7
The equation of PQ is
y = -(3/7)x + b
To find b, note that the line passes through the point (7,6). Therefore
6 = -(3/7)*7 + b
6 = -3 + b
b = 9
The equation of PQ is
y = - (3/7)x + 9
or
7y = -3x + 63
3x + 7y = 63
Answer: 3x + 7y = 63