Answer:
f^-1(x)=³√[(x+7)÷4]
Step-by-step explanation:
f(x)=4x^3-7
y=4x^3-7
interchange 'y' with 'x'
x=4y^3-7
make y the subject
4y^3=x+7
divide by 4 both sides
y^3=(x+7)÷4
multiply by the cube root both sides
³√(y^3)=³√[(x+7)÷4]
y=³√[(x+7)÷4]
f^-1(x)=³√[(x+7)÷4]
Step-by-step explanation:
step 1. The square matrices are C and D.
step 2. If you add up the top rows you get 2, 8, -4 .
step 3. The answer is B.
Answer:
<h3>
9, 10 and 11</h3>
Step-by-step explanation:
x - the smallest of three consecutive integers (the first)
x+1 - the next of three consecutive integers (the second)
x+2 - the last of three consecutive integers (the third)
3(x+2) - three times the third integer
<u>3(x+2)+x </u> - three times the third increased by the first
5(x+1) - five times the second tnteger
<u>5(x+1)-8 </u> - 8 less than five times the second
3(x + 2) + x = 5(x + 1) - 8
3x + 6 + x = 5x + 5 - 8
4x + 6 = 5x - 3
-4x -4x
6 = x - 3
x = 9
x+1 = 10
x+2 = 11
Check: 3×11+9 = 33+9 = <u>42</u>, 5×10-8=50-8 = <u>42</u>
4 x 4 x 4 x 4 x 4
I think that’s the answer
