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padilas [110]
3 years ago
5

Solve the system using the substitution method 6x - 2y = -4 y= 3x + 2

Mathematics
2 answers:
Oksana_A [137]3 years ago
4 0

Answer:

x= -0.66+0.33

Step-by-step explanation:

you already have what y equals, so the next step is to plug in the solution for y into  6x - 2y = - 4

-plug in y = 3x + 2 into 6x - 2y = - 4 through the y variable

-making the equation now 6x - 2(3x + 2) = - 4

-now solve for x by distributing -2 to 3x and +2

6x - 6x - 4 = - 4 ------> - 4 = - 4

6x - 2y = - 4 -----> 6x = - 4 + 2y -----> x = - 0.66 + 0.33

Anit [1.1K]3 years ago
3 0

Answer:

Step-by-step explanation:

6x - 2y = -4

y= 3x + 2

We see that y = 3x + 2 so we can use that value of Y everytime we see i in the other equation.

6x - 2(3x +2) = -4

Now usually we'd we simply solve for X.

6x - 6x -4 = -4

This clearly does not work as we cannot get rid of X

Therefore, this system of equations has no solution we can find through substitution

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multiply both sides by 2 to eliminate the fraction

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As a check

\frac{1}{2} × 56 = 28 ← True


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Step-by-step explanation:

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Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

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Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

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W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

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