Ask question

Ask question

All categories

3 years ago

5

Which of the equations below can be solved by square roots? How would you solve the other equation? Explain your reasoning. Give

the solutions to both equations. Equation A: x? - 9x = 0 Equation B : x2-9=0

1 answer:

Kaylis [27]3 years ago

3 0

Answer:

Equation A is factoring, x=9 and x=0

Equation B is the square root, x=3

You might be interested in

Kelly has 24 dimes and quarters worth $3.60. How many quarters does she have?

son4ous [18]

Should be around 5 (five) quarters

7 0

4 years ago

Read 2 more answers

-3 * f(-8) + 7 * g(2)

enyata [817]

Answer:

-2(-12-7 g)

Step-by-step explanation:

hope this helps :)

3 0

3 years ago

33x-21x=-24+12 <br> I need help on this math problem. Thanks

lions [1.4K]

X=3. 33x-21x equals 12x. 24+12=36. 12x divided by 36 equals 3

8 0

4 years ago

Can someone answer this question please answer it correctly please answer it correctly

tatiyna

I am fairly certain it’s C 1.07X since that would include both the tax and its original price

7 0

3 years ago

Read 2 more answers

The ratio of 14C to 12C in living organisms is 1.3 × 10-12. The fossilized remains of an organism are discovered and the ratio o

soldi70 [24.7K]

Answer:

t = 8588 years

Step-by-step explanation:

From the given information:

Using the formula:

$k = \dfrac{In (2)}{t_{1/2}}$

Given that:

$t_{1/2}$ = 5730 years

Then:

$k = \dfrac{In (2)}{5730}$

$k = \dfrac{0.6931472}{5730}$

k = 1.20968 × 10⁻⁴

However; the expression to find the value of x is:

$x= x_oe^{-kt}$

$4.6 \times 10^{-13} = 1.3 \times 10^{-12} \times e^{(-1.20968\times 10^{-4} \times t)}$

$\dfrac{4.6 \times 10^{-13} }{1.3 \times 10^{-12}}= e^{(-1.20968\times 10^{-4} \times t)}$

$0.353846= e^{(-1.20968\times 10^{-4} \times t)}$

(-1.20968 × 10⁻⁴ × t) = In(0.353846)

(-1.20968 × 10⁻⁴ × t) = -1.03889

$t = \dfrac{-1.03889}{-1.20968 \times 10^{-4}}$

t = 8588 years

8 0

4 years ago