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nekit [7.7K]
3 years ago
12

How do i solve an absolute prblem

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0


Step 1: Isolate the absolute value expression.Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.Step 3: Solve for the unknown in both equations.Step 4: Check your answer analytically or graphically.



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Can someone tell me the answer for this <br><br><br> I got this wrong on my first attempt ._.
dimaraw [331]

Answer:

86°

Step-by-step explanation:

This is a circle theorem question, specifically the cyclic quadrilateral theorem.

If you have a a 4-sided shape that touches the circumference of the circle with all 4 vertices, it's know as a cyclic quadrilateral.

The theorem states: "Opposite angles in a cyclic quadrilateral add up to 180°"

We want the angle at point L so we subtract the opposite angle to L (Angle J, which is 94°), so 180 - 94 = 86

The neat thing is that it's still a quadrilateral, and if you find all the remaining sides, they should add up to 360°, just like a regular square or rectangle.

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Answer:

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Step-by-step explanation:


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4 years ago
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Based on the family the graph below belongs to, which equation could represent the graph?
saul85 [17]

Answer:

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Find the perimeter and area of this figure
Sonja [21]

Answer:

A = (16π -32) in²

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Step-by-step explanation:

The area is that of a quarter-circle of radius 8 inches less half the area of a square with side length 8 inches. Two formulas are useful:

area of a circle = πr² . . . . .r = radius

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Then your area is ...

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The applicable formulas for the side lengths of your figure are ...

arc BD = (1/4)(2πr) = π(r/2) = π(8 in)/2 = 4π in

segment BD = (8 in)√2

The perimeter is the sum of these lengths, so is ...

P = (4π +8√2) in

_____

Of course, you are very familiar with the fact that an isosceles right triangle with side lengths 1 has a hypotenuse of length √(1²+1²) = √2. Scaling the triangle by a factor of 8 inches means the segment AB will be 8√2 inches long.

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3 years ago
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