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Volgvan
3 years ago
9

On a coordinate plane, triangles A B C and D E F are shown. Triangle A B C has points (4, 2), (7, 2), (4, 6). Triangle D E F has

points (negative 2, negative 1), (4, negative 3), and (4, negative 1).
How do the areas of triangle ABC and DEF compare?

The area of △ABC is 1 square unit less than the area of △DEF.
The area of △ABC is equal to the area of △DEF.
The area of △ABC is 1 square unit greater than the area of △DEF.
The area of △ABC is 2 square units greater than the area of △DEF.
Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0

Answer:

A

Step-by-step explanation:

got it right on edge

guajiro [1.7K]3 years ago
3 0

Answer:

A

Step-by-step explanation:

I just did it

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Given:

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Line segment AB partition in the ratio 1 : 5.

To find:

The coordinate of a point that partitions AB.

Solution:

Section formula:

$P(x,y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+m y_{1}}{m+n}\right)

Here x_1=16, y_1=4, x_2=34, y_2=40 and m = 1, n = 5

$P(x,y)=\left(\frac{1\times 34+5 \times 16}{1+5}, \frac{1\times 40+5 \times4}{1+5}\right)

$P(x,y)=\left(\frac{ 34+80}{6}, \frac{40+20}{6}\right)

$P(x,y)=\left(\frac{ 114}{6}, \frac{60}{6}\right)

$P(x,y)=(19, 10)

The coordinate of point that partitions the segment AB is (19, 10).

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