On a coordinate plane, triangles A B C and D E F are shown. Triangle A B C has points (4, 2), (7, 2), (4, 6). Triangle D E F has
points (negative 2, negative 1), (4, negative 3), and (4, negative 1). How do the areas of triangle ABC and DEF compare?
The area of △ABC is 1 square unit less than the area of △DEF.
The area of △ABC is equal to the area of △DEF.
The area of △ABC is 1 square unit greater than the area of △DEF.
The area of △ABC is 2 square units greater than the area of △DEF.
In this situation triangle BOC is inscribed in the circle. Length of BC is 10,91, length of BO is 5 (radius) and length of CO is 5 (radius). we need to know theorem of sines:
