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1 year ago

Find the value of W that makes quadrilateral PQRS a parallelogram.

Mathematics

1 answer:

mestny [16]1 year ago

6 0

to be a parallelogram its front sides must be equal to each other

so, we equalize the length of two sides that are face to face

$\begin{gathered} 5w-25=w+15 \\ \\ \end{gathered}$

and solve for w

$\begin{gathered} 5w-w=15+25 \\ 4w=40 \\ w=\frac{40}{4} \\ \\ w=10 \end{gathered}$

the value of w must be 10

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3 years ago

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3 years ago

Read 2 more answers

What is the slope of the line that passed through the points (8,6) and (-2, 10)

lbvjy [14]

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3 years ago

Given lines p and q are parallel, m<2 - (14x - 12), m<6 - (5y + 23), and m<8 - (8x + 27), solve for the values of x and

nexus9112 [7]

Answer:

x = 7.5

y = 14

m<1 = 87°

m<7 = 93°

Step-by-step explanation:

Given:

m<2 = (14x - 12),

m<6 = (5y + 23),

m<8 = (8x + 27)

m<2 + m<8 = 180° (consecutive exterior angles are supplementary)

(14x - 12) + (8x + 27) = 180 (substitution)

Solve for x

14x - 12 + 8x + 27 = 180

Collect like terms

22x + 15 = 180

Subtract 15 from each side

22x = 180 - 15

22x = 165

Divide both sides by 22

x = 7.5

m<2 = m<6 (corresponding angles are congruent)

(14x - 12) = (5y + 23) (substitution)

Plug in the value of x

14(7.5) - 12 = 5y + 23

105 - 12 = 5y + 23

93 = 5y + 23

Subtract 23 from each side

93 - 23 = 5y

70 = 5y

Divide both sides by 5

14 = y

y = 14

✅m<1 = m<8 (alternate exterior angles are congruent)

m<1 = (8x + 27) (substitution)

Plug in the value of x

m<1 = 8(7.5) + 27 = 87°

m<7 = m<2 (alternate exterior angles are congruent)

m<7 = (14x - 12) (substitution)

Plug in the value of x

m<7 = 14(7.5) - 12 = 93°

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2 years ago