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MaRussiya [10]
3 years ago
7

Pls help and give steps pls I give brainliest thank uuuu

Mathematics
2 answers:
user100 [1]3 years ago
7 0

Answer:

\boxed{Volume \: of \:  rectangular \: prism = 42 \: {cm}^{3}}

Explanation:

Volume of rectangular prism is same as volume of cuboid

Length = 3 cm

Width = 7 cm

Height = 2 cm

Volume of rectangular prism = Length × Width × Height

= 3 × 7 × 2

= 3 × 14

= 42 cm³

krek1111 [17]3 years ago
6 0

Answer: 42 cm to the power of 3

Step-by-step explanation: L x w x h

3 x 7 x 2

21 x 2

42

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

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So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

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         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


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     =0.7408182207^{4}

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           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

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1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

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