Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
Answer:
809, 708, 607, 506, 405, 304, 203, 102, 1, -100
Step-by-step explanation:
809, 708, 607, _____, _______
First term = 809
Second term = 708
Third term = 607
Difference between first term and second term = 809 - 708
= 101
Difference between second term and third term = 708 - 607
= 101
Therefore, the common difference is 101
Fourth term = 607 - 101
= 506
Fifth term = 506 - 101
= 405
Sixth term = 405 - 101
= 304
Seventh term = 304 - 101
= 203
Eighth term = 203 - 101
= 102
Ninth term = 102 - 101
= 1
Tenth term = 1 - 101
= - 100
809, 708, 607, 506, 405, 304, 203, 102, 1, -100
Answer:
5902
Step-by-step explanation:
Solution: 13% off 45400 is equal to (13 x 13) / 100 = 5902.
Answer:2/5, 1/2, 5/8, 2/3
Step-by-step explanation:
im in 10th grade i thin k i know my fractions
