4 1/6 = 4 7/42
2 4/7 = 2 24/42
2 24/42 + 4 7/42 = 6 31/42
6 31/42 = 283/42
37. 37-4=33 33÷3=11 hope i helped
I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
D is the answer that is graphed.
Answer:
31
Step-by-step explanation:
4 squared is 16, and 5 times 3 is fifteen if you add them you get 31
