Answer:
$2000 was invested at 5% and $5000 was invested at 8%.
Step-by-step explanation:
Assuming the interest is simple interest.
<u>Simple Interest Formula</u>
I = Prt
where:
- I = interest earned.
- P = principal invested.
- r = interest rate (in decimal form).
- t = time (in years).
Given:
- Total P = $7000
- P₁ = principal invested at 5%
- P₂ = principal invested at 8%
- Total interest = $500
- r₁ = 5% = 0.05
- r₂ = 8% = 0.08
- t = 1 year
Create two equations from the given information:


Rewrite Equation 1 to make P₁ the subject:

Substitute this into Equation 2 and solve for P₂:





Substitute the found value of P₂ into Equation 1 and solve for P₁:



$2000 was invested at 5% and $5000 was invested at 8%.
Learn more about simple interest here:
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Answer:
There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean is:

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.
Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.
The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).
The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Answer:
342
Step-by-step explanation:
x=5
72+72+18(5)+9+18 (5)+9=342
You can make a table like this:
If 1 bag=5 pounds
Then 6 bags must equal six times the weight of the first bag
5 times 6=30
Your answer is reasonable because 5+5+5+5+5+5=30
a.k.a
=5 =30
Answer:
56
Step-by-step explanation:
By tracing the lines on the tree diagram, we see the probability of both being red is 0.5 × 0.6 = 0.3.
The probability of both being blue is 0.5 × 0.4 = 0.2.
So we would expect to get both blue 2/3 of the times we get both red.
X = 2/3 (84)
X = 56