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mojhsa [17]
3 years ago
9

A jet can fly at a rate of 480 mi/h in calm air. Traveling with the wind, the plane flew 1560 mi in the same amount of time it t

ook to fly 1320 mi against the wind. Find the rate of the wind.
Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

Let the Rate of the Wind be : W mi/h

Given : The Jet can fly at a rate of 480 mi/h

⇒ Travelling with the Wind, Jet flies with a speed of (480 + W) mi/h

⇒ Travelling against the Wind, Jet flies with a speed of (480 - W) mi/h

Given : The Jet Travels 1560 Miles, Travelling with the Wind

<u>Let us calculate How much time the Jet takes to Travel 1560 Miles</u>

In One Hour : The Jet travels a Distance of (480 + W) Miles

⇒ The Jet travels a Distance of 1560 Miles in : [\frac{1560}{480 + W}]\;Hours

Given : The Jet Travels 1320 Miles, Travelling against the Wind

<u>Let us calculate How much time the Jet takes to Travel 1320 Miles</u>

In One Hour : The Jet travels a Distance of (480 - W) Miles

⇒ The Jet travels a Distance of 1320 Miles in : [\frac{1320}{480 - W}]\;Hours

Given : Time taken to fly 1560 Miles with the Wind = Time taken to fly 1320 Miles against the Wind.

⇒ \frac{1560}{480 + W} = \frac{1320}{480 - W}

⇒ 1560(480 - W) = 1320(480 + W)

⇒ (1560 × 480) - 1560W = (1320 × 480) + 1320W

⇒ 1560W + 1320W = (1560 × 480) - (1320 × 480)

⇒ 2880W = 480(240)

⇒ 288W = 48(240)

⇒ 72W = 12(240)

⇒ 6W = 240

⇒ W = 40

⇒ The Rate of Wind is 40 mi/h

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MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
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Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

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You can get rid of \lambda from these equations and you would get

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And from those equations you would get

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If we plug in what we just got, we would have

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