From the calculations, the rate of growth of the culture is 2.88.
<h3>What is exponential growth problem?</h3>
We apply the exponential growth problem when there is an exponential increase.
Thus, we have; P =Poe^rt
P = amount at time t
Po = amount originally present
t = time taken
r = rate of growth
1.6 × 10^6 = 16e^4r
1.6 × 10^6/16 = e^4r
1.0 * 10^5 = e^4r
ln 1.0 * 10^5 = ln e^4r
11.5 = 4r
r = 11.5/4
r = 2.88
Learn more about exponential growth:brainly.com/question/11487261
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Answer: Process B because it will reduce our dependency on fossil fuels.
Explanation:
Biofuels are the fuels which are produce by animals and plants matter. These fuels are generated by renewable sources like plants and animals which can be grown again for production of these fuels. These fuels limits our dependency on non-renewable fuels like coal, petrol and natural gas. Therefore, the non renewable fuels will remain available to fulfill the future generation needs. Hence, will help in conservation.
<span><em>Whether living or non living:</em>
<em>When you put a sample of tissue under a microscope, if u can see a cell membrane, and can identify some cell structures like nucleus, mitochondria, vacuoles etc. , it was living, if not, its a non living thing.</em></span>
<span><em>However some cells don't have a nucleus( eg. prokaryotic cells), but all cells have a cell membrane or some sort of protective covering to contain the cell's insides. </em></span>
<span><em>To check if your specimen maybe-once living, maybe-still living "something", is living, get a look at it through an electron microscope - thats the best microscope ever- and see if the mitochondria's making any ATP( adenosine triphosphate, source of energy for most organisms), if it does, its living. If not, no</em></span><em>n living. :)</em>
Answer:
100%
Explanation:
This question involves two genes in guinea pigs; one coding for fur color and the other for fur length. The alleles of black fur (B) and short fur (F) is dominant over the alleles for brown fur (b) and long fur (f).
In a cross between two offsprings with genotypes: BBFF x bbff, the following gametes will be produced by each parent:
BBFF - BF, BF, BF, and BF
bbff - bf, bf, bf, bf
Using these gametes in a punnet square (see attached image), one will notice that all of the offsprings will have the genotype: BbFf i.e all or 100% of the offsprings are heterozygous for both of the genes or traits.