The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.
<h3>What is the chi-squared test statistic?</h3>
Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.
The formula for the chi-squared test statistic is;

Where,
is the observed value
is the expected value
The chi-square test statics is;

Hence, the chi-squared test statistic will be 3.11.
To learn more about the chi-squared test statistic refer;
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Answer:
1:
p-r/6=-6-(-6)/6=-6+1=<u>-</u><u>5</u>
<u>2</u><u>:</u>
<u>p-</u><u>(</u><u>m-n</u><u>)</u><u>=</u> -1-(-4-4)=-1-(-8)=-1+8=<u>7</u>
3:
(z+y)/2)3=(-5-4)/3=-9/3=<u>-</u><u>3</u>
<u>4</u><u>:</u>
m/6-n=6/6-6=1-6=<u>-</u><u>5</u>
5:
k³-h=3³-(-2)=27+2=<u>2</u><u>9</u>
6:
p-(p-(m-3))=5-(5-(4-3))=5-(5-1)=5-4=<u>1</u>
7:
(k)(k-j)+3=(5)(5-5)+3=5*0+3=<u>3</u>
8.
p²/6-q=6²/6-4=6-4=<u>2</u>
<u>9</u><u>;</u>
zx+3³=6*4+3³=24+27=<u>5</u><u>1</u><u>.</u>
<u>1</u><u>0</u><u>:</u>
<u>y</u><u>+</u><u>z</u><u>-</u><u>(</u><u>y</u><u>-</u><u>x</u><u>)</u><u>=</u>5+4-(5-2)=9-3=<u>6</u>
<u>S</u><u>o</u><u>m</u><u>e</u><u> </u><u>b</u><u>a</u><u>s</u><u>i</u><u>c</u><u> </u><u>r</u><u>u</u><u>l</u><u>e</u><u>s</u><u>:</u>
+. +. +=+
+. * +=+
+. ÷ +=+
+. - +=+
and
+. +. -=add and put sigh of greater one.
-. * +=-sigh
-÷-=+sigh
- - -=add and put - sigh
The anwser is 1/4 or 25% or .25
I'll give you the equation with the problem's plugged in, but not the answer.
Formula: Volume = Base x Height
1. B= 5 in; H= 6 in; 5 x 6 = ?
2. B= 54 m; H= 5 m; 54 x 5 = ?
Answer:
89.125%
Step-by-step explanation:
The weighted mean is simply the multiplication of the number of student in each period times the respective average of said period, divided by the total number of students:
Average =
= 89.125%