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Svetllana [295]
2 years ago
8

PLEASE HURRY NO LINKS OR FILES OR I'LL REPORT I CAN GIVE BRAINLIEST

Mathematics
1 answer:
marissa [1.9K]2 years ago
5 0

Answer:

3 1/3

Step-by-step explanation:

2 + (-2/3)² ÷ 1/3

2 + 4/9 ÷ 1/3

2 + 4/9 × 3/1

2 + 12/9  =  2 + 4/3  =  2 + 1 1/3

= 3 1/3

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Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

P(X > x) = \frac{b - x}{b - a}

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that a = 0.95, b = 1.05

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

P(X > x) = 0.9

So

\frac{1.05 - x}{1.05 - 0.95} = 0.9

1.05 - x = 0.9*0.1

x = 1.05 - 0.9*0.1

x = 0.96

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

4 0
3 years ago
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Answer:

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3 years ago
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8 0
3 years ago
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Sergeu [11.5K]

Answer:3*(7*d)+(4e)=3*7d+4e

Step-by-step explanation:

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2 years ago
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tia_tia [17]

Answer:

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Step-by-step explanation:

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