Just subtract 6-6 and 8-6 then divide 1/2 by both sides
Answer: -√1/✓41
Step-by-step explanation:
Let y be the irrational number that will be multiplied by -√41 to get the product that equals 1.
y × (-√41) = 1
We then solve for y, by dividing through with -√41. This will be:
[y × (-√41)]/-√41 = 1/-√41
y = -1/√41
y = -√1/✓41
The irrational number is negative root one over root forty one.
The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
Answer:
75, 89, 91, 105, 107, 121, 123, 137
Step-by-step explanation:
If you analyze how much each number is increased, you will notice it alternates between adding 2, then adding 14:
11 + 14 = 25.
25 + 2 = 27.
27 + 14 = 41.
41 + 2 = 43.
43 + 14 = 57.
57 + 2 = 59.
59 + 14 = 73.
That means you can simply, finish the pattern, alternating between adding 2 and 14. Then you will get these answers.
Vas happenin!
Hope your day is going well
I think it’s A
Sorry if it’s wrong
Hope this helps *smiles*
