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RoseWind [281]
3 years ago
6

A hospital gives a survey to all surgical patients asking them to rate the quality of their hospital experience. One month after

surgery, the hospital contacts the patients again to ask if there were any complications from the surgery. Last year, the results of the surveys showed that of the patients who had a poor hospital experience, 90% had post-surgical complications. What conclusion can be drawn from this study?
Poor hospital experiences cause post-surgical complications.

Some patients who have a poor hospital experience also have post-surgical complications.

Post-surgical complications cause poor hospital experiences.

Most patients who have a poor hospital experience also have post-surgical complications.
Mathematics
2 answers:
wel3 years ago
5 0
<h2>Answer:</h2>

Option D is the correct answer.

Step-by-step explanation:

Given is :

Last year, the results of the surveys showed that of the patients who had a poor hospital experience, 90% had post-surgical complications.

Most patients who have a poor hospital experience also have post-surgical complications.

This is because, 90% is the large percentage of a population, when it says 'most people'. This can be summarized as every 9 out of 10 patients had poor hospital experience as well as post surgical complications.

Therefore, option D is the right answer.

polet [3.4K]3 years ago
4 0
Hey there,
The answer is - <span>Some patients who have a poor hospital experience also have post-surgical complications.

Hope this helps :))

<em>~Top♥</em>
</span>
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Answer:

69

Step-by-step explanation:

m1 = 180 - (180 - 39 - 30) = 180 - 111 = 69

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Look at the stem-and-leaf plot.
cestrela7 [59]
The answer is c 10 #s are greater than 110
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Use the graph below to answer the question that follows:
Alborosie

Answer:

Step-by-step explanation:

x 1 = π ,  x 2 = 3 π/ 2

y 1 = - 1,  y 2 = 2

The Rate of change = ( y 2 - y 1) / ( x 2 - x 1 )=

= [2 -( -1 )] : ( 3 π /2 - π ) = 3 : π/2 = 6 / π <em>≈ 1.91 </em>

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2 years ago
2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation whic
Artemon [7]
<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

\sf{\rightarrow{d =  kt}}

\sf\rightarrow{20  = 2k }

\sf\rightarrow{K= \frac{20}{2} }

\sf\rightarrow{K={\color{magenta}{10}}}

<h2><u>Answer</u>:-</h2>
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3 0
3 years ago
A bakery works out a demand function for its chocolate chip cookies and finds it to be q = D (x) = 943 - 17 x​, where q is the q
Alex73 [517]

Answer:

See expla below

Step-by-step explanation:

Given the demand function:

q = D (x) = 943 - 17 x

a) Find the elasticity:

Find the derivative of the demand function.

D'(x)= -17

Thus, elasticity expression is:

\frac{x D'(x)}{D'(x)}

= \frac{x (-17)}{943 - 17x}

= \frac{17x}{943 - 17x}

Elasticity expression = E(x) = \frac{17x}{943 - 17x}

b) At what price is the elasticity of demand equal to 1?

This means E(x) = 1

Substitute 1 for E(x) in the elasticity equation:

E(x) = \frac{17x}{943 - 17x}

1 = \frac{17x}{943 - 17x}

Cross multiply:

943 - 17x = 17x

Collect like terms

17x + 17x = 943

34x = 943

x = \frac{943}{34}

x = 27.74

Elasticity at the price of demand = 1 is 27.74

c) At what prices is the elasticity of demand elastic?

This means E(x) > 1

Therefore,

\frac{17x}{943 - 17x} > 1

\frac{17x}{943 - 17x} > 1

Cross multiply:

17x > 943 - 17x

Collect like terms

17x + 17x > 943

34x > 943

x > \frac{943}{34}

x > 27.74

The elasticity of demand is elastic at x > 27.74

d) At what prices is the elasticity of demand inelastic?

This means E(x) < 1

Therefore,

\frac{17x}{943 - 17x} < 1

\frac{17x}{943 - 17x} < 1

Cross multiply:

17x < 943 - 17x

Collect like terms

17x + 17x < 943

34x < 943

x < \frac{943}{34}

x < 27.74

The elasticity of demand is inelastic at x < 27.74

e) At what price is the revenue a maximum:

Total  revenue will be:

R(x) = x D(x)

= x (943 - 17x)

= 943x - 17x²

R(x) = 934 - 17x(price that maximizes total revenue)

Take R(x) = 0

Thus,

0 = 943 - 17x

17x = 943x

x = \frac{943}{17}

x = 27.74

Total revenue is maximun at x= 27.74 per cookie

f) At x = 21 per cookie, find the price:

Thus,

R (21) = (943 * 21) - (17 * 21²)

= 19803 - 7497

= 12306

At x = 27.74, find the price:

R(27.74) = (943 * 27.74) - (17 - 27.74²)

= 26158.82 - 13081.63

= 13077.19

We can see the new price of cookie causes the total revenue to decrease.

Therefore, with a small increase in price the total revenue will decrease.

5 0
3 years ago
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