Answer:
The answer is below
Step-by-step explanation:
A store carries four brands of DVD players, J, G, P and S. From past records, the manager found that the relative frequency of brand choice among customers varied. Using the given probability values for each of the four brands, find the probability that a random customer will choose brand J or brand P.
P(J)=0.22, P(G)=0.18, P(P)=0.35, P(S)=0.25
Answer: Probability is the ration of possible outcomes to the total number of possible outcomes. The probability of mutually exclusive events i.e. events that cannot occur at the same time is the sum of their individual probabilities. If two events A and B are mutually exclusive events, then:
P(A or B) = P(A) + P(B)
Given that P(J)=0.22, P(G)=0.18, P(P)=0.35, P(S)=0.25, the probability that a random customer will choose brand J or brand P is given by:
P(J or P) = P(J) + P(P) = 0.22 + 0.35 = 0.57
Given:
0.1% of all transactions are fraudulent
99% correct identification whether a transaction is fraudulent or not.
Scanned 5,000,000 transactions.
5,000,000 x 0.1% = 5,000 fraudulent transactions.
For me, there are 5,000 fraudulent transactions. This is based on the 0.1% rather than the 99%. Because the problem clearly states that the 0.1% of ALL transaction is identified as fraudulent. The 99% of the computer program only deals with the correct identification of the transaction as either fraudulent or not. For me, it is not a clear measure of the true number of fraudulent transactions.
this is false not all equations and all equations are identities are same
Answer:
14% were running backs 43/50 were not running backs
Step-by-step explanation:
0.14=14%
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1-0.14=0.86
50x0.86=43
