Missing question: How many executives should be surveyed?
Solution:
Mean = 13 hours
SD = 3 hours
Confidence level = 95%
Mean viewing time within a quarter of an hour = 0.25 = 1.96*3/sqrt (N)
Where N = Sample population
N = {(1.96*3)/0.25}^2 = 553.19 ≈ 554
Therefore, 554 executives should be surveyed to yield such results.
3/4 on the minute hand of a clock would be 45.
example: 6:45
If you round 100.360 to the nearest whole number it'll be (100) if you see "100.500" i'll be 101 due to the decimals
You draw a straight line and then put your number on the line. If you have to find a negative number, you can just go below zero. Positive numbers on a number line are always above zero. Hope this helps!
Answer:
Total possible number of outcomes = C(24,6) [24 choose 6]
=24!/(6!18!)
= 134596
Out of which there is only one winning combination.
Therefore we conclude:
P(win 20000)=1/134596
P(lose 1)=134595/134596
and hence the expected value is:
20000*(1/134596)+(-1)*(134595/134596)
=-114595/134596
=-0.8514 (rounded to four places after decimal)
Step-by-step explanation:
Hope this helped!
