Answer:
(-8,4)
Step-by-step explanation:
Given: 2x-3y=-28 and x+6y=16
solve for a variable and then substitute back into other equation
x + 6y = 16
x = 16 - 6y; now use this in the other equation
2x - 3y = -28; substitute into x
2(16 - 6y) - 3y = -28; distribute 2
32 - 12y - 3y = -28; combine y's
32 - 15y = -28; isolate 15y
32 + 28 = 15y; add the numbers
60 = 15y; divide by 15
y = 4
Now use this to plug into other equation
x + 6y = 16; y=4
x + 6(4) = 16;
x + 24 = 16; subtract 24 from both sides
x = -8
Correct Answer: A. 2(n+8).
Answer:
1. 
2. ![(p^2-6)[1-q(p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%28p%5E2-6%29%5D)
Step-by-step explanation:
1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.
Then the expression. 
remains as:
2. The first thing to do to factor the expression is to take the expression 
as its common factor with its lowest exponent.
Then the expression 
remains as:
![(p^2-6)[1-q (p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%20%28p%5E2-6%29%5D)
Answer:
40 is the answer I also got 40
