Greetings I am BrotherEye
Answer:
The Task you are asking me to complete is nearly impossible for me to complete in under a short window f twenty Minutes furthermore I will conduct a guide to asist you in asymbling your Orgnizer. Types of Graphic Organizers to Improve Learning
T-Chart.
Concept Map.
Main Idea Web.
Venn Diagram.
Sequence Chart.
Step-by-step explanation:
Please pick one and I will you
~
BrotherEye
Answer:
Class width = 20
Approximate lower class limit of the first class = 110
Approximate Upper class limit of the first class = 119
Step-by-step Explanation:
The class width of the histogram attached below can be gotten by finding the difference between successive lower class limits.
Thus, class width = 130 - 110 = 20
The approximate lower class limit of the first class is the lowest score we have in the first class = 110
The approximate upper class limit of the first class is the closest highest score that fall within the first class and is below the lower limit of the second class. Thus approximate upper class limit of the first class = 129
STEP-BY-STEP EXPLANATION:
Given information:
Let x be the number
Mathematically, the statement can be translated below as

The next step is to represent it on a tape diagram
Answer:
idk ask someone else
Step-by-step explanation:
idk bro sorry
Answer:
An equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....
Step-by-step explanation:
The given expression is:
x2-16x+12
Break the constant term:
x^2-16x-36 +48=0
[x^2-16x-36] +48=0
Now break the middle term inside the brackets
(x^2-18x+2x-36)+48=0
Take the common
[x(x-18) +2(x-18)]+48=0
(x-18)(x+2)+48=0
Thus an equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....