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ehidna [41]
4 years ago
13

The Parks and recreation department in your town offers a season pass for $150.

Mathematics
1 answer:
Black_prince [1.1K]4 years ago
7 0

The system of equations are p = 150 + 5n and p = 15n

<u>Solution:</u>

Given that, The Parks and recreation department in your town offers a season pass for $150.  

With the season pass you pay $5 per session to use the town's tennis courts.  

Without the season pass you pay $15 per session to use the tennis courts.

We have to write a system of equations to represent the situation

Now, let the number of sessions be "n" and total paying amount be "p"

<em><u>Then in case of taking season pass  </u></em>

total amount = season pass cost + $5 per session

p = 150 + 5 x n  

p = 150 + 5n  

<em><u>And in case of no season pass</u></em>

total amount = 15 per session

p = 15 x n  

p  = 15n

Hence, the system of equations are p = 150 + 5n and p = 15n

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Answer:

The required co-ordinate is (-2, -5).

Step-by-step explanation:

For a given point, reflection of a point (x, y) across a horizontal line y = k, the reflected co-ordinates will be: $ R_{y = k} = (x, 2k - y) $.

Here, (x, y) = (-2, 7) then reflection along the line y = 1, we get:

$ R_{y = 1} (-2, 7) = (-2, 2(1) - 7) $

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4 years ago
Annie goes shopping for vacation She buys 5 beach towels and 3 bathing suits and she spent $56. If the items are all the same pr
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$7

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3 years ago
Y=4x-6 and passes through point 8,12
umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

<u><em>Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.</em></u>

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

y=mx+b\\y=4x-20

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

y=mx+b\\y=-\frac{1}{4} x+14

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3 years ago
PLZ ANSWER &lt;3
Oksi-84 [34.3K]

Answer:

hang on give me a sec to edit this

it is.

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3 years ago
Read 2 more answers
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