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IRINA_888 [86]
3 years ago
8

Hàm số nào là hàm lẻ A sin^2 x+1 B cot^3x C tn3x cotx d cosx

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0
{(sin (x))^2A(csc(x))^3(cos))3B+(-3x)
{cot (dx) cos (x)
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Describe the pattern, write the next term, and write a rule for the nth term of the sequence,
vagabundo [1.1K]

Step-by-step explanation:

Next term is - 51

Use formula Tn=a+(n-1)d

a=the first term of the sequence which is - 15

d=the difference between the terms which is - 9

Substitute

Tn=-15+(n-1)(-9)

Tn=-15+9-9n

Tn=-9n-6

From this you will be able to generate all the terms in the pattern

If they say determine the 50th term just substitute 50 by n

Tn=-9(50)-6

Tn=-450-6

Tn=-456

7 0
3 years ago
A _______ is a group of people who agree to save their money together and to make loans to each other at a relatively low rate o
Law Incorporation [45]
A Credit union is a group of people who agree to save their money together and to make loans to each other at a relatively low rate of interest. <span />
7 0
3 years ago
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Can someone help me with graphing this function?
Paul [167]

p.s. Excuse the scribble.

Step-by-step explanation:

This is a piece-wise function. The three intervals we need to worry about are [0, 1), [1,2], and [2,4].

Separate the functions into their pieces and draw out the individual graphs. Place them together onto the graph within their respective intervals.

5 0
3 years ago
What is the area of the rectangle, in square feet?<br>9 ft<br>20 ft​
goblinko [34]

Answer:

180 Square Feet

Step-by-step explanation:

For Rectangle:

l = 9 ft

b = 20 ft

Area of Rectangle

= l \times b \\  = 9 \times 20 \\  = 180 \:square \:  feet

3 0
3 years ago
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

where t_{0.025} is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
3 years ago
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