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IRINA_888 [86]
2 years ago
8

Hàm số nào là hàm lẻ A sin^2 x+1 B cot^3x C tn3x cotx d cosx

Mathematics
1 answer:
Sedaia [141]2 years ago
6 0
{(sin (x))^2A(csc(x))^3(cos))3B+(-3x)
{cot (dx) cos (x)
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Rotate ΔABC with vertices A(-1, 4), B(2, 1), and C(3, -3) about the origin by 90°.
MAXImum [283]
You got this you can do it I don’t know the answer but I hope you find someone who does(:
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3 years ago
Evaluating numeric expressions <br> 16^5/4X16^1/4/(16^1/2)^2=?
Sever21 [200]

Answer: 2^14

Step-by-step explanation:

7 0
3 years ago
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A total of 632 tickets were sold for the school play. They were either adult tickets or student tickets. There were 68 fewer stu
STALIN [3.7K]
Answer 384

Explanation
In total 632 and there were either adult or students so
632/2=316
So because it said 68 tickets were sold less for the students I added it to 316
316+68=384

Adults=384

I hope this helps if I’m wrong someone please correct me
3 0
2 years ago
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The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate
Schach [20]

Answer:

(a)0.16

(b)0.588

(c)[s_1$ s_2]=[0.75,$  0.25]

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix P^k.

(a)

P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}

If the system is initially running, the probability of the system being down in the next hour of operation is the (a_{12})th$ entry of the P^2$ matrix.

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, S=[s_1$  s_2]

[s_1$  s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$  s_2]

Using a calculator to raise matrix P to large numbers, we find that the value of P^k approaches [0.75 0.25]:

Furthermore,

[0.75$  0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$  0.25]

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

[s_1$ s_2]=[0.75$  0.25]

4 0
3 years ago
Juno is taking a taxi. The table represents a linear function and shows the amount she owed after various numbers of miles trave
Gennadij [26K]

(B) - Yes, because the amount owed changes by 2.25 every time the miles change by 1.


Starting at 1 mile the price is 2.5 dollars.

Mile 2 is 4.75 dollars. What is the difference between 4.75 and 2.5? 2.25

Mile 3 is 7 dollars. What is the difference between 7 and 4.75? 2.25

Mile 4 is 9.25 dollars. What is the difference between 9.25 and 7? 2.25

Mule 5 is 11.5 dollars. What is the difference between 11.5 and 9.25? 2.25

The change is always 2.25 dollars.

The change is 2.25 dollars per mile.

One way to solve for this is (11.5 - 2.5)/(5-1)=2.25

This is (y2-y1)/(x2-x1). By picking 2 points, (x1,y1) and (x2,y2) you can solve for the slope (rate of change) between them.

7 0
2 years ago
Read 2 more answers
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