Answer:
The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.
Explanation:
Given:-
- The diameter of the drill bit, d = 98 cm
- The power at which drill works, P = 5.85 hp
- The rotational speed of drill, N = 1900 rpm
Find:-
What Torque And Force Is Applied To The Drill Bit?
Solution:-
- The amount of torque (T) generated at the periphery of the cutting edges of the drilling bit when it is driven at a power of (P) horsepower at some rotational speed (N).
- The relation between these quantities is given:
T = 5252*P / N
T = 5252*5.85 / 1900
T = 16.171 Nm
- The force (F) applied at the periphery of the drill bit cutting edge at a distance of radius from the center of drill bit can be determined from the definition of Torque (T) being a cross product of the Force (F) and a moment arm (r):
T = F*r
Where, r = d / 2
F = 2T / d
F = 2*16.171 / 0.98
F = 33 N
Answer: The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.
Answer:
Energy released as heat will be -189.417 Kj
Explanation:
The oxidation is the type of reaction in which reaction occurs in the presence of oxygen. The exothermic reaction is the type of reaction in which heat is released. The enthalpy is the type of physical quantity that is used to measure the energy in the thermodynamic system.
As we know the molar mass of Copper II Oxide is 79.545 g
Also the oxidation of copper(II) oxide, CuO(s), is an exothermic process, 2Cu2O (s) + O2-->4CuO (s) delta H reaction= -292.0 kj/mol.
So for 51.60g of Copper II Oxide,
Heat released will be (-292.0 * 51.60/79.545) = -189.417 Kj
Answer:The slope in the velocity-time graph represents the acceleration. The slope is defined as the ratio of change in y-axis to change in the x-axis. The slope is represented by the letter m and following is the general formula used for determining the slope:
Explanation:
Injuries that are warm and not cold or hot.
