Answer:
u = 104.68 m/s
Explanation:
given,
horizontal distance = 150 m
elevation of 12.4 m
angle = 8.6°
horizontal motion = x = u cos θ. t .............(1)
vertical motion =
................(2)
from equation(1) and (2)
..........{3}
![12.4 = 150\times tan (8.6) - \dfrac{9.8\times 150^2}{2u^2cos^2(8.6)}](https://tex.z-dn.net/?f=12.4%20%3D%20150%5Ctimes%20tan%20%288.6%29%20-%20%5Cdfrac%7B9.8%5Ctimes%20150%5E2%7D%7B2u%5E2cos%5E2%288.6%29%7D)
![\dfrac{9.8\times 150^2}{2u^2cos^2(8.6)} = 10.29](https://tex.z-dn.net/?f=%5Cdfrac%7B9.8%5Ctimes%20150%5E2%7D%7B2u%5E2cos%5E2%288.6%29%7D%20%3D%2010.29)
![\dfrac{9.8\times 150^2}{2\times 10.29\times cos^2(8.6)} = u^2](https://tex.z-dn.net/?f=%5Cdfrac%7B9.8%5Ctimes%20150%5E2%7D%7B2%5Ctimes%2010.29%5Ctimes%20cos%5E2%288.6%29%7D%20%3D%20u%5E2)
![u = \sqrt{10959.34}](https://tex.z-dn.net/?f=u%20%3D%20%5Csqrt%7B10959.34%7D)
u = 104.68 m/s
The initial speed of the ball is u = 104.68 m/s
Answer: ![0.69\°](https://tex.z-dn.net/?f=0.69%5C%C2%B0)
Explanation:
The angular diameter
of a spherical object is given by the following formula:
![\delta=2 sin^{-1}(\frac{d}{2D})](https://tex.z-dn.net/?f=%5Cdelta%3D2%20sin%5E%7B-1%7D%28%5Cfrac%7Bd%7D%7B2D%7D%29)
Where:
is the actual diameter
is the distance to the spherical object
Hence:
![\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})](https://tex.z-dn.net/?f=%5Cdelta%3D2%20sin%5E%7B-1%7D%28%5Cfrac%7B16%20m%7D%7B2%281338%20m%29%7D%29)
This is the angular diameter
The true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.
In Physics, we define a wave as a disturbance along a medium that transfers energy. The wavelength of a wave is the distance covered by the wave while the frequency of the wave is the number of cycles of the wave completed per second.
The period of the wave is the inverse of the frequency of the wave. It is defined as the time taken for the wave to complete a cycle and it is measured in seconds.
The wave formula is given as;
v = λf
v = velocity of the wave (distance traveled by the wave in one second)
λ = wavelength of the wave
f = frequency of the wave
So;
λ = 32.4 cm
f = 3 hertz
v = 32.4 cm × 3 hertz
v = 97. 2 cms-1
Hence, the true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.
Learn more: brainly.com/question/14588679
Answer:
C. ![\frac{3F}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3F%7D%7B8%7D)
Explanation:
Let initial charges on both spheres be,![q](https://tex.z-dn.net/?f=q)
![F=\frac{Kq^2}{d^2} \ \ \ \ \ \ \ \ \ \ \_i](https://tex.z-dn.net/?f=F%3D%5Cfrac%7BKq%5E2%7D%7Bd%5E2%7D%20%20%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%20%5C%20%5C_i)
When the sphere C is touched by A, the final charges on both will be,![\frac{q}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bq%7D%7B2%7D)
#Now, when C is touched by B, the final charges on both of them will be:
![q_c=q_d=\frac{q/2+q}{2}\\\\=\frac{3q}{4}\\](https://tex.z-dn.net/?f=q_c%3Dq_d%3D%5Cfrac%7Bq%2F2%2Bq%7D%7B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B3q%7D%7B4%7D%5C%5C)
Now the force between A and B is calculated as:
![F\prime=\frac{k\times\frac{q}{2}\times \frac{3q}{4}}{d^2}\\F\prime=\frac{3F}{8}](https://tex.z-dn.net/?f=F%5Cprime%3D%5Cfrac%7Bk%5Ctimes%5Cfrac%7Bq%7D%7B2%7D%5Ctimes%20%5Cfrac%7B3q%7D%7B4%7D%7D%7Bd%5E2%7D%5C%5CF%5Cprime%3D%5Cfrac%7B3F%7D%7B8%7D)
Hence the electrostatic force becomes 3F/8