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3 years ago

What is the transfer of heat from a stove burner to a pan on the burner called?

Physics

2 answers:

liq [111]3 years ago

6 0

Answer: Option (a) is the correct answer.

Explanation:

When two substances of different temperatures are in contact with each other then transfer of heat takes place from a hotter substance to the colder substance. This process is called conduction.

For example, a pan placed on the stove burner then heat will transfer from stove burner to the pan.

When a fluid (liquid or gas) is heated then more denser (cold) material will sink at the bottom whereas less denser (hot) material will rise at the top. This process is known as convection.

For example, boiling of rice in a pot filled with water.

Radiation is defined as the transfer of wave-like motion of heat energy through an empty space.

For example, heating of a metal plate by radiations from the Sun.

Thus, we can conclude that the transfer of heat from a stove burner to a pan on the burner called conduction.

Serga [27]3 years ago

5 0

I think the correct answer from the choices listed above is the first option. the transfer of heat from a stove burner to a pan on the burner is called conduction. This type of heat transfer is the exchange of thermal energy between physical systems by molecular agitation within a material without any motion of the material as a whole.

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A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity = 4.184 J/g K) at initial temperatur

BARSIC [14]

Answer : The molar heat of solution for the salt is 452.9 kJ/mole

Explanation :

First we have to calculate the heat of solution.

$q=m\times c\times \Delta T$

where,

q = heat of solution = ?

c = specific heat of water = specific heat of solution = $4.184J/g.K=4.184J/g^oC$

m = mass of solution = 107.093 g

Mass of solution = Mass of water + Mass of salt
Mass of solution = 100.000 g + 7.093 g = 107.093 g

$\Delta T$ = change in temperature = $T_2-T_1=(80.000-61.128)=18.872^oC=$

Now put all the given values in the above formula, we get:

$q=107.093g\times 4.184J/g^oC\times 18.872^oC$

$q=8456.111J=8.456kJ$

Now we have to calculate the molar heat of solution for the salt, in kJ/mol.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = molar heat of solution = ?

q = heat required = 8.456 kJ

m = mass of salt = 7.093 g

Molar mass of salt = 379.984 g/mol

$\text{Moles of salt}=\frac{\text{Mass of salt}}{\text{Molar mass of salt}}=\frac{7.093g}{379.984g/mole}=0.01867mole$

$\Delta H=\frac{8.456kJ}{0.01867mole}=452.9kJ/mole$

Therefore, the molar heat of solution for the salt is 452.9 kJ/mole

4 0

3 years ago

A force used to lift a 25kg mass to a height of 12m in 5 sec does 2100J of work. How much force is used

Citrus2011 [14]

Work = force × distance
21000 = force × 12m

we need to rearrange this equation because force isn't on the right side of the equation and it becomes

force = 2100 ÷ 12m
force = 175N

7 0

3 years ago

A car travels West at 35 mph for a time period of 2.5 hours and then travels West at 55 mph for an additional time of 4.0 hours.

OlgaM077 [116]

The total distance travelled is 307.5 miles.

<h3>What is the distance covered?</h3>

We know that the distance covered can be obtained from the formula from speed since the motion all took place in the same direction.

Speed = distance/time

distance = speed * time

In the first case;

Distance = 35 mph * 2.5 hours = 87.5 miles

In the second case;

Distance = 55 mph * 4.0 hours = 220 miles

Total distance = 87.5 miles + 220 miles = 307.5 miles

Hence the total distance travelled is 307.5 miles.

Learn more about total distance:brainly.com/question/20330990

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2 years ago

jamie is not sure a new medication will work because it has not had a large test group. Is jamie being creative?

elena-s [515]

No, they're being skeptical.

4 0

3 years ago

Read 2 more answers

The flow rate over Niagara falls is 84,760 cfs (cubic feet per second), and the drop from top to bottom is 167 feet. If this flo

jekas [21]

To develop this problem we will calculate the volume from the given flow (volume per unit of time). This process will be accompanied by transforming the units given in the International system.

Through the density-volume-mass ratio, we will calculate the mass. Finally we will proceed to calculate the total power generated.

1 feet = 0.3048 m

$\dot{V} = 84760ft^3/s$

$\dot{V} = 84760ft^3/s (\frac{(0.3058m)^3}{(1ft)^3})$

$\dot{V} = 2400m^3/s \text{and the Volume each second is } V= 2400m^3$

Now the mass of water falling down each second would be

$\rho = \frac{m}{V} \rightarrow m = \rho V$

$m = (1000kg/m^3)(2400m^3)$

$m = 2.4*10^6kg$

Now Height in meters is

$h = 167 ft (\frac{(0.3058m)}{(1ft)})$

$h= 50.9 m$

The power produced is equivalent to the work done by gravity over a certain time. At this case that can be expressed as,

$P = \frac{W}{t}\\P = \frac{F*h}{t}\\P = \frac{mgh}{t}\\P = \frac{2.4*10^6*9.8*50.9}{1}\\P = 1.197*10^9 Watts$

The power of Niagara Falls then would be 1.197GW while the power generated by the Three Gorges Dam is 22,500 MW. This indicates that the Niagara Falls, if it were a dam that covered 100% of the fluid it carries, would exceed the production of the dam in China by thousands.

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4 years ago