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saul85 [17]
3 years ago
12

Consider two isolated, charged conducting spheres: a large sphere and a second smaller sphere with a radius 6 times smaller than

that of the large sphere, but with 3 times as much charge.
(a) Calculate the ratio of the electric potential at the surface of the large sphere to that of the small sphere.

Physics
1 answer:
Troyanec [42]3 years ago
4 0

Let the bigger sphere be sphere 1 and the let the smaller sphere be sphere 2. Rest of the answer is in the picture.

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Plz help me ASAP How does sound travel from its source to your ear??? 1. By changes in air pressure 2. By vibrations in wires or
Sholpan [36]

Answer:

2. By vibrations in wires or strings.

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4 years ago
A baseball bat exerts an average force of 600. newtons east on a ball, imparting an impulse of
Anvisha [2.4K]

Answer: The time of contact will be 0.006 seconds.

Explanation:

An impulse of a force is the product of average force and the time interval when the force acts.

Mathematically,

J=F\Delta t

Where,

J = impulse = 3.6 Ns

F = Force = 600N

\Delta t = Time = ?s

Putting the values in above equation, we get:

3.6Ns=600N\times t

t = 0.006 seconds

Hence, the time of contact will be 0.006 seconds.

3 0
3 years ago
Read 2 more answers
A sled with no initial velocity accelerates at rate of 5.0 m/s^2 down a hill . How long does it take the sled to go 45 m to the
Leya [2.2K]

The time taken by the sled to reach 45 m to the bottom is 4.24 s.

The sled's initial velocity <em>u</em> is zero. It has an acceleration <em>a</em> of a value 5 m/s² down the hill and it travels a distance <em>s</em> equal to 45 m down the hill.

Use the equation of motion,

s=ut+\frac{1}{2} at^2

Substitute 0 m/s for u and rewrite the equation for t.

t=\sqrt{\frac{2s}{a}}  \\ =\sqrt{\frac{2(45 m)}{5.0m/s^2} } \\ =4.24s

The sled takes a time of 4.24 s to reach the bottom of the hill

6 0
4 years ago
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777dan777 [17]
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3 0
3 years ago
A block weighing 87.0 N rests on a plane inclined at 24.1° to the horizontal. The coefficient of the static and kinetic friction
Tom [10]

Answer:

15.7 N

Explanation:

Draw a free body diagram.  The block has four forces acting on it.  Gravity pulling down, normal force pushing perpendicular to the plane, friction pointing up the plane, and applied force F pushing up the plane.

Sum of the forces normal to the plane:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the plane:

∑F = ma

Nμ + F − mg sin θ = 0

F = mg sin θ − Nμ

Substituting:

F = mg sin θ − mgμ cos θ

F = mg (sin θ − μ cos θ)

Given mg = 87.0 N, θ = 24.1°, and μ = 0.25 (because the block is not moving):

F = 87.0 N (sin 24.1° − 0.25 cos 24.1°)

F = 15.7 N

4 0
3 years ago
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