The number of the meals possible is 350.
The complete question is given below:-
A menu has 5 choices of appetizers, ten main courses, and seven desserts. How many meals are possible?
<h3 /><h3>What is the combination?</h3>
The arrangement of the different things or numbers in a number of ways is called the combination.
Given that:-
- A menu has 5 choices of appetizers, ten main courses, and seven desserts.
The number of the combination of the meals will be calculated as:-
N = 5 x 10 x 7
N = 350
Therefore the number of the meals possible is 350.
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Hello!
To find the line parallel to the line x + 2y = 6 and passing through the point (1, -6), we will need to know that if two lines are parallel, then their slopes are equivalent to each other.
Since the given equation is written in standard form, we will need to change it to slope-intercept form to get the slope. Slope-intercept form is: y = mx + b.
x + 2y = 6 (subtract x from both sides)
2y = 6 - x (divide both sides by 2)
y = 6/2 - x/2
y = -1/2x + 3 | The slope of parallel lines are -1/2.
Since we are given the slope, we need to find the y-intercept of the line that goes through the point (1, -6) by substituting that point into a new equation with a slope of m equalling to -1/2.
y = -1/2x + b (substitute the given point)
-6 = -1/2(1) + b (simplify - multiply)
-6 = -1/2 + b (add 1/2 to both sides)
b = -11/2 | The y-intercept of the parallel line is -13/2.
Therefore, the line parallel to x + 2y = 6 and goes through the ordered pair (1, -6) is y = -1/2x + -11/2.
First, distribute to cancel out brackets
= m-n+p-2m+2p-3n-n+m-2p
Collect like terms
= -5n+p
Your answer: -5n + p
Hope this helped :)
