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djyliett [7]
3 years ago
12

How many moles of sulfur atoms are in 9.9 moles of Ag2S

Chemistry
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

9.9 moles of Ag₂S contain 9.9 moles of sulfur.

Explanation:

Given data:

Number of moles of Ag₂S = 9.9 mol

Number of moles of Sulfur = ?

Solution:

One mole of Ag₂S having 1 mole of sulfur.

In 9.9 moles:

9.9 moles × 1 = 9.9 moles

So 9.9 moles of Ag₂S contain 9.9 moles of sulfur.

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A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titra
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Answer:

See explanation below

Explanation:

In order to calculate this, we need to use the following expression to get the concentration of the base:

MaVa = MbVb (1)

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Atomic weights of the elements to be used:

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MM KHP = (1.0078*5) + (39.0983) + (8*12.0107) + (4*15.999) = 204.2189 g/mol

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With the moles, we also know that:

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n = MbVb

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Mb = n/Vb  (3)

Finally, replacing the data:

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Mb = 0.184 M

This would be the concentration of NaOH

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3 years ago
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