Answer is: 4.02 <span>grams of water are required.
</span>Chemical reaction: BaH₂ + 2H₂O → Ba(OH)₂ + 2H₂.
Ideal gas law: p·V =
n·R·T.<span>
p = 755 mm Hg </span>÷ 760.0 mmHg / atm = 0.993<span> atm.
T = 25 + 273.15 = 298.15 K.
V(H</span>₂) <span>= 5.50 L.
R = 0,08206 L·atm/mol·K.
n(H</span>₂)
= <span>0.993 atm · 5.5 L ÷ 0,08206 L·atm/mol·K · 298.15 K.
n(H</span>₂)
= 0.223 mol.<span>
From chemical reaction: n(H</span>₂O) : n(H₂) = 1 : 1.<span>
n</span>(H₂O) = 0.223 mol.<span>
m</span>(H₂O) =
0.223 mol · 18 g/mol.<span>
m</span>(H₂O) =
4.02 g.
In the area of positive charge, neutral body gets negative charge for making a dipole whereas when negative charge bought near neutral one, it gets positive charge for the same reason.........making polarization
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, since the potassium bromide and silver nitrate are in a 1:1 mole ratio, the first step is to identify the limiting reactant, by considering the reacting volumes of reactants in order to compute the available moles of potassium bromide and the moles of potassium bromide consumed by the 15.4 mL of 0.512-M solution of silver nitrate:
In such a way, since less moles are consumed than available, we infer that silver nitrate is the limiting reactant, for which the resulting grams of silver bromide (molar mass 187.8 g/mol) result:
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