How many is too many

A wave like the one shown in the diagram below is called a transverse wave. Such a wave is typical of light waves and other type

raketka [301]

Answer: transmits yellow light

Explanation:

5 0

3 years ago

Compare the first ionization energy of sodium to that of potassium

stellarik [79]

Answer:

Sodium is higher than Potassium in thesame group

Explanation:

Sodium and potassium are the elements present in the first group of the periodic table. In group, atomic size increases from top to bottom this implies that even atomic radius increases. This causes less attraction force by nucleus on the electrons of outermost orbit of the atom and hence reduces the first ionisation energy, which is the energy required to remove the electron from the outermost orbit of an atom. So, as potassium is below sodium in the group, sodium has greater ionisation energy than potassium

3 0

4 years ago

A student was asked to determine the concentration of ammonia, a volatile substance used in the clinical setting as a respiretor

UNO [17]

This question is describing two chemical equations whereby the concentration of ammonia has to be determined. The first reaction is between 25.00 mL of ammonia and 50.00 mL of 0.100-M HCl whose excess was neutralized with 21.50 mL of 0.050-M Na₂CO₃ and thus, the concentration ammonia in the cloudy solution was determined as 0.114 M.

First of all we need to go over the titration of the excess HCl with Na₂CO₃ by writing the chemical equation it takes place when they react:

$2HCl+Na_2CO_3\rightarrow 2NaCl+CO_2+H_2O$

Whereas the mole ratio of HCl to Na₂CO₃ is 2:1 and the volume of the HCl leftover is determined as follows:

$V_{HCl}^{leftover}=\frac{2*0.050M*21.50mL}{0.100M} =21.5mL$

Next, we infer that the consumed volume of HCl by the ammonia solution was:

$V_{HCl}^{consumed}=50.00mL-21.50mL=28.5 mL$

Then, we write the chemical equation that takes place between ammonia and HCl:

$HCl+NH_3\rightarrow NH_4Cl$

Whereas the mole ratio is now 1:1, which means that the concentration of ammonia was:

$M_{NH_3}=\frac{28.5mL*0.100M}{25.00mL}\\\\ M_{NH_3}=0.114M$

Learn more:

(Titration) brainly.com/question/15687419
(Titration) brainly.com/question/25328286

8 0

2 years ago

A gas has a of 590 mi. At a temperature What volume will the gas occupy at 30.0öc.1 Which gas law is this

scoray [572]

The given question is incomplete. The complete question is:

A gas has a volume of 590 ml at a temperature of $0^0C$ .What volume will the gas occupy at $30.0^0C$ . Which gas law is this?

Answer: 655 ml , Charle's Law

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$