The quotient rule is
d(u/v) = (u dv - v du) / u2

d(u/v) can written as
d( u (1/v) )

Using the product rule and chain rule
d( u (1/v)) = u d(1/v) + (1/v) du
= u (-1/v2) dv + (!/v) du
= (u dv - v du) / u2

5 0

2 years ago

Calculate limits x>-infinity -2x^5-3x+1

Lera25 [3.4K]

Given:

The limit problem is:

$\lim_{x\to -\infty}(-2x^5-3x+1)$

To find:

The value of the given limit problem.

Solution:

We have,

$\lim_{x\to -\infty}(-2x^5-3x+1)$

In the function $-2x^5-3x+1$ , the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

$\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$

Therefore, $\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$ .

3 0

2 years ago

60000+7000+900 in short form​

60000+7000+900 in short form