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Firlakuza [10]
2 years ago
5

Someone please help!

Mathematics
1 answer:
svetoff [14.1K]2 years ago
7 0

Answer:

a =6

b=4

c=2

step-by-step explanation:

\sqrt{x^{12} y^{9}z^{5} }   = \sqrt{x^{12} y^{8}y z^{4} z}  = \sqrt{(x^{6}) ^{2} (y^{4}) ^{2} (z^{2})^{2} yz }  = x^{6}y^{4} z^{2}  \sqrt{yz}

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This is a simple A^2 + B^2 = C^2 Pythagorean Theorem problem.

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Imagine a right triangle with 2 legs and a hypotenuse.
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