The available source of charge that pushes a charge through a circuit is

An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.

Aleksandr-060686 [28]

The tension in the upper rope is determined as 50.53 N.

<h3>Tension in the upper rope</h3>

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

T(u) is tension in upper rope
T(d) is tension in lower rope

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

Learn more about tension here: brainly.com/question/918617

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6 0

2 years ago

An angler experiences a glare of light coming from the water's surface. Which type of glasses should she wear to minimize the gl

Vaselesa [24]

The glasses that she should wear are the glasses that block horizontally polarized light coming from glares, like polaroid sunglasses, because these type of glasses block out the light being reflected from the water's surface by the vertically oriented polarizers in the lenses.

6 0

3 years ago

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What is the advantages and disadvantages of 'howe' truss?

Vinvika [58]

Answer:

Advantages: Very sturdy, can have several cracks in structure before breaking

disadvantages: best for short distances, not attractive, hard to maintain

6 0

4 years ago

Write down the conservation of momentum?

otez555 [7]

Law of conservation of momentum states that when two objects collide with each other , the sum of their linear momentum always remains same or we can say conserved and is not effected by any action, reaction only in case is no external unbalanced force is applied on the bodies.
Let,
m
A

= Mass of ball A
m
B

= Mass of ball B
u
A

= initial velocity of ball A
u
B

= initial velocity of ball B
v
A

= Velocity after the collision of ball A
v
B

= Velocity after the collision of ball B
F
ab

= Force exerted by A on B
F
ba

= Force exerted by B on A
Now,
Change in the momentum of A= momentum of A after the collision - the momentum of A before the collision
= m
A

v
A

−m
A

u
A

Rate of change of momentum A= Change in momentum of A/ time taken
=
t
m
A

v
A

−m
A

u
A

Force exerted by B on A (F
ba

);
F
ba

=
t
m
A

v
A

−m
A

u
A

........ [i]
In the same way,
Rate of change of momentum of B=
t
m
b

v
B

−m
B

u
B

Force exerted by A on B (F
ab

)=
F
ab

=
t
m
B

v
B

−m
B

u
B

.......... [ii]
Newton's third law of motion states that every action has an equal and opposite reaction, then,
F
a

b=−F
b

a [ ' -- ' sign is used to indicate that 1 object is moving in opposite direction after collision]

Using [i] and [ii] , we have
t
m
B

v
B

−m
B

u
B

=−
t
m
A

v
A

−m
A

u
A

m
B

v
B

−m
B

u
B

=−m
A

v
A

+m
A

u
A

Finally we get,
m
B

v
B

+m
A

v
A

=m
B

u
B

+m
A

u
A

This is the derivation of conservation of linear momentum.

5 0

3 years ago

The 20-g bullet is travelling at 400 m/s when it becomes embedded in the 2-kg stationary block. The coefficient of kinetic frict

nikklg [1K]

Answer:

The distance the block will slide before it stops is 3.3343 m

Explanation:

Given;

mass of bullet, m₁ = 20-g = 0.02 kg

speed of the bullet, u₁ = 400 m/s

mass of block, m₂ = 2-kg

coefficient of kinetic friction, μk = 0.24

Step 1:

Determine the speed of the bullet-block system:

From the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

v is the speed of the bullet-block system after collision

(0.02 x 400) + (2 x 0) = v (0.02 + 2)

8 = v (2.02)

v = 8/2.02

v = 3.9604 m/s

Step 2:

Determine the time required for the bullet-block system to stop

Apply the principle of conservation momentum of the system

$v(m_1+m_2) -F_kt = v_f(m_1 +m_2)\\\\v(m_1+m_2) -N \mu_kt = v_f(m_1 +m_2)\\\\v(m_1+m_2) -g(m_1 +m_2) \mu_kt = v_f(m_1 +m_2)\\\\3.9604(2.02)-9.8(2.02)0.24t = v_f(2.02)\\\\8 - 4.751t = 2.02v_f\\\\3.9604 - 2.352t = v_f$

when the system stops, vf = 0

3.9604 -2.352t = 0

2.352t = 3.9604

t = 3.9604/2.352

t = 1.684 s

Thus, time required for the system to stop is 1.684 s

Finally, determine the distance the block will slide before it stops

From kinematic, distance is the product of speed and time

$S = \int\limits {v} \, dt \\\\S = \int\limits^t_0 {(3.9604-2.352t)} \, dt\\\\ S = 3.9604t - 1.176t^2$

Now, recall that t = 1.684 s

S = 3.9604(1.684) - 1.176(1.684)²

S = 6.6693 - 3.3350

S = 3.3343 m

Thus, the distance the block will slide before it stops is 3.3343 m

3 0

4 years ago

Read 2 more answers