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3 years ago

8

While practicing the trumpet you notice that every time you play a particular note a window in the room rattles. How can you exp

lain this rattling in terms of wave behaviors?

1 answer:

kherson [118]3 years ago

7 0

The sound waves travel because of the pitch of the note so the window rattles.

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A long, thin superconducting wire carrying a 17 A current passes through the center of a thin, 3.0-cm-diameter ring. A uniform e

nalin [4]

Answer:

a

$\frac{dE}{dt} =- 2.72 *10^{15} \ N/C \cdot s$

b

The direction of the electric field is opposite that of the current

Explanation:

From the question we are told that

The current is $I = 17\ A$

The diameter of the ring is $d = 3.0 \ cm = 0.03 \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2}$

$r = \frac{0.03}{2}$

$r = 0.015 \ m$

The cross-sectional area is mathematically represented as

$A = \pi r^2$

=> $A = 3.142 * (0.015^2)$

=> $A = 7.07 *10^{-4 } \ m^ 2$

Generally according to ampere -Maxwell equation we have that

$\oint \= B \cdot \= ds = \mu_o I + \epsilon_o \mu _o\frac{ d \phi }{dt }$

Now given that $\= B = 0$ it implies that

$\oint \= B \cdot \= ds = 0$

So

$\mu_o I + \epsilon_o \mu _o\frac{ d \phi }{dt } = 0$

Where $\epsilon _o$ is the permittivity of free space with value $\epsilon_o = 8.85*10^{-12 } \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

$\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} N/A^2$

$\phi$ is magnetic flux which is mathematically represented as

$\phi = E * A$

Where E is the electric field strength

So

$\mu_o I + \epsilon_o \mu _o \frac{ d [EA] }{dt } = 0$

=> $\frac{dE}{dt} =- \frac{I}{\epsilon_o * A }$

=> $\frac{dE}{dt} =- \frac{17}{8.85*10^{-12} * 7.07*10^{-4} }$

=> $\frac{dE}{dt} =- 2.72 *10^{15} \ N/C \cdot s$

The negative sign shows that the direction of the electric field is opposite that of the current

8 0

3 years ago

A cart's initial velocity is +3.0 meters per second. What is its final velocity after accelerating at a rate of 1.5 m/s2 for 8.0

Katarina [22]

Answer:

V = 15m/s

Explanation:

Given the following data;

Initial velocity = 3m/s

Time = 8secs

Acceleration = 1.5m/s²

To find the final velocity, we would use the first equation of motion;

V = U + at

Substituting into the equation, we have

V = 3 + 1.5*8

V = 3 + 12

V = 15m/s

6 0

3 years ago

3 bulbs are in series and the same 3 bulbs are in parallel with the same battery. Which bulbs will be dimmer?

salantis [7]

The bulbs connected in series will be dimmer.

<h3>What is a series connection?</h3>

When there is a connection in series, it implies that the connection is done in an end to end fashion. When the connection is in parallel the it is made in such a way that the bulbs are joined to a common junctions the same potential difference occurs across then all.

Now we know that in a series connection, the voltage across the different bulbs varies hence there is a potential drop which accounts for the decrease in the brightness of the bulb. On the other hand, the voltage across a parallel connection is the same thus the bulbs do not dim so much.

Hence, if 3 bulbs are in series and the same 3 bulbs are in parallel with the same battery, the bulbs connected in series will be dimmer.

Learn more about series connection:brainly.com/question/18713901

#SPJ1

5 0

2 years ago

The bar ab has a velocity at point a of va = [20,9] m/s and an angular velocity w = 23 rad/s. If the distance between a and b is

DiKsa [7]

speed of point A is given as

$v_a = 20.9 m/s$

$v_a = r*\omega$

here r = distance from the axis

so here we have

$20.9 = r*23$

$r = 0.91 m$

now the distance of point A and B is 0.71 m

while the distance of axis from point A is 0.91 m

so distance of axis from point B will be given as

$r = 0.91 + 0.71 = 1.62 m$

now for the speed of point b is given as

$v = r \omega$

$v = 1.62 * 23$

$v = 37.26 m/s$

so end point B will move with speed 37.26 m/s

8 0

3 years ago

A liquid of density 1270 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the f

FinnZ [79.3K]

Answer:

${P_2}-P_1=49.99\ KPa$

Explanation:

$v_1=9.43\ m/s$

$d_1=11.7\ cm/s$

$d_2=17.5\ cm/s$

From continuity equation

$A_1v_1=A_2v_2$

$v_1d_1^2=v_2d_2^2$

$v_2=\dfrac{9.43\times 11.7^2}{17.5^2}$

$v_2=4.21\ m/s$

$\dfrac{P_1}{\rho g}+\dfrac{v_1^2}{2g}+y_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}+y_2$

${P_1}+\rho\dfrac{v_1^2}{2}+\rho y_1g={P_2}+\rho\dfrac{v_2^2}{2}+\rho y_2g$

$\rho\dfrac{v_1^2}{2}+\rho y_1g -\rho\dfrac{v_2^2}{2}-\rho y_2g={P_2}-P_1$

$1270\times \dfrac{9.43^2}{2}+1270\times 0\times 10 -1270\times\dfrac{4.21^2}{2}-1270\times 0.175\times 10={P_2}-P_1$

${P_2}-P_1=49.99\ KPa$

4 0

3 years ago