Answer:
Power = 21.6 Watts
Explanation:
Power = 
Where W = work and t = time.
W = Fs
Where F is force and s is displacement.
29.6N(5.9m) = 174.64J
W = 174.64J
Power = 
Power = 21.6 Watts
Chemosynthetic bacteria or chemoautotropic bacteria is the new bacteria that was found by scientists in a hot water sulfur spring that uses sulfur as a source of energy instead of sunlight. This kind of bacteria can survive at a higher temperature than most organisms can.The bacteria uses the toxic hydrogen sulfide to produce organic materials by the process of chemosynthesis. These bacteria are a source of life for several other organisms that flourish in such conditions. The bacteria grows and forms a thick mat and this attracts several other organisms as the bacteria becomes a source of food.
Answer:
C
Explanation:
speed if how far an object goes whereas the velocity is the speed in hour or a minute
To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzmann law which establishes that a black body emits thermal radiation with a total hemispheric emissive power (W / m²) proportional to the fourth power of its temperature.
Heat flow is obtained as follows:

Where,
F =View Factor
A = Cross sectional Area
Stefan-Boltzmann constant
T= Temperature
Our values are given as
D = 0.6m

The view factor between two coaxial parallel disks would be


Then the view factor between base to top surface of the cylinder becomes
. From the summation rule


Then the net rate of radiation heat transfer from the disks to the environment is calculated as





Therefore the rate heat radiation is 780.76W
Answer:
D) 21
Explanation:
When gas absorbs light , electron at lower level jumps to higher level .
and the difference of energy of orbital is equal to energy of radiation absorbed.
Here energy absorbed is equivalent to wavelength of 91.63 nm
In terms of its energy in eV , its energy content is eual to
1243.5 / 91.63 = 13.57 eV. This represents the difference the energy of orbit .
Electron is lying in lowest or first level ie n = 1.
Energy of first level
= - 13.6 / 1² = - 13.6 eV.
Energy of n th level = - 13.6 / n². Let in this level electron has been excited
Difference of energy
= 13.6 - 13.6 / n² = 13.57 ( energy of absorbed radiation)
13.6 / n² = 13.6 - 13.57 = .03
n² = 13.6 / .03 = 453
n = 21 ( approx )