Answer:
The correct answer is:
Includes at least two groups, one of which does not receive the experimental treatment. (B)
Explanation:
A controlled experiment is made up of at least two groups of participants (subjects). One group (the test group) receives the experimental treatment, which can be an intervention or a new drug to be tested etc, and the effect of the treatment on the subjects is measured, while the second group of similar subjects also known as the control group acts as a baseline and do not receive the treatment or intervention. They act as a baseline to ensure that the change observed in the treatment group was brought about as a result of the treatment.
<em>Note that repeating the experiment several times does not ensure accuracy of the result, rather it ensures reliability of the results hence option D is not correct</em>
Answer:
Spore
Explanation:
Most of the fungal species reproduce through spores. Spores are the reproductive structures of fungi that help in the survival of fungal species under unfavorable conditions and their dispersal to new habitats. Fungal spores are very light in weight and are dispersed with wind currents.
For example, ascospores are the sexual spores produced by fungal species of the group ascomycetes and are carried with the wind.
Answer: 0.05 M
Explanation:
Para responder esta pregunta, hay que tener en cuenta la Ley de Conservación de la Masa. <u>La misma indica que en una reacción química en un sistema cerrado, la masa total de las moléculas que participan permanece constante.</u> Esto significa que la masa utilizada en los reactivos es la misma que la masa de los productos generados.
En este problema, se cuenta con una solución de NaOH (hidróxido de sodio) tiene una molaridad de 0.204 (siendo la molaridad el número de moles por litro de solución) y se utilizan 16.4 mL de dicha solución para agregarla a 50 mL de una solución de H3PO4 (ácido fosfórico).
Entonces, ya que la masa de ambas soluciones no se pierde, podemos utilizar la ecuación de la Ley de Conservación de la Masa:
Concentración inicial x Volumen inicial = Concentración final x Volumen final.
Concentración inicial: 0.204 M
Volumen inicial: 16.4 mL
Concentración final: ?
Volumen final: 50 mL + 16.4 mL = 66.4 mL
Reemplazamos los valores en la ecuación:
0.204 M x 16.4 mL = Concentración final x 66.4 mL
La molaridad de la solución de H3PO4 es de 0.05 M.
I think that the answer is: true
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