Answer:
No solution
Step-by-step explanation:
So first we have to Distribute;
-3x + 3 > -3x - 2
This is an solution which means that they can never intersect on a graph.
We can solve further if you want;
Add 3x to both sides;
The x cancel themselves out.
3 > -2
I think A would be correct
Let's solve this problem step-by-step.
STEP-BY-STEP EXPLANATION:
First, we will establish that the shape of the window is a semi-circle. This means we must use the formula for the perimeter of a semi-circle to obtain the perimeter of the window.
The formula for the perimeter of a semi-circle is as follows:
Let perimeter of window or semi-circle = P
P = [ 2( Pi )r / 2 ] + 2r
Where r = radius of circle or semi-circle
From this, we will simply use the value of the radius given from the diagram in the problem and substitute it into the formula to obtain the perimeter of the window.
P = [ 2( Pi )r / 2 ] + 2r
r = 20
THEREFORE:
P = [ 2( Pi )( 20 ) / 2 ] + 2( 20 )
P = 20( Pi ) + 40
P = 102.83...cm^2
P = 102.8cm^2 ( to the nearest tenth )
FINAL ANSWER:
Therefore, the perimeter of the window is 102.8cm^2 ( to the nearest tenth ).
Hope this helps! :)
Have a lovely day! <3
Answer:
The area of the regular nonagon is 7921.8 square inches.
Step-by-step explanation:
Geometrically speaking, the area of a regular polygon is determined by following area formula:
(1)
Where:
- Area of the regular polygon, in square inches.
- Perimeter, in inches.
- Apothem, in inches.
If we know that
and
, then the area of the regular nonagon is:

The area of the regular nonagon is 7921.8 square inches.
Answer:
See below
Step-by-step explanation:
(a) Field lines
A negatively charged particle has an electric field associated with it.
The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.
Opposite charges attract, so the field lines point toward the centre of the particle.
For an isolated negative particle, the field lines would look like those in Figure 1 below.
If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.
A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.
We can make a similar statement about appositive charge approaching from the left.
Thus, there are few field lines in the region between the two particles.
(b) Coulomb's Law
The formula for Coulomb's law is
F = (kq₁q₂)/r²
It shows that the force varies inversely as the square of the distance between the charges.
Thus, the force between the charges decreases rapidly as they move further apart.