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FrozenT [24]
3 years ago
5

A 3.0 µF capacitor is initially connected to a 6.0 V battery. Once the capacitor is fully charged the battery is removed and a 4

.0 Ω resistor is connected between the two terminals of the capacitor. Find the current flowing through the resistor 14.0 µsec after the capacitor begins to be discharged.
Physics
1 answer:
Otrada [13]3 years ago
3 0

Answer:

i=-66.6\times10^{-6}\;\;Amp

Explanation:

Given,

C=3\mu F\\V=6.0 volt\\R=4\Omega\\t=14\mu sec\\

Now, charge in capacitor

q_o=CV\\q_o=3\times10^{-6}\times6\\q_o=18\times10^{-6}\;\;C

For discharging the RC circuit,

q=q_oe^{-t/\tau}

Differentiate with respect to the <em>'t'</em>

\frac{dq}{dt}=-q_o\frac{t}{RC}e^{t/RC}\\i=-q_o\frac{t}{RC}e^{t/RC}\\i=-18\times10^{-6}\frac{14\times10^{-6}}{4\times3\times10^{-6}}e^{\frac{14\times10^{-6}}{4\times3\times10^{-6}}}\\i=-66.6\times10^{-6}\;\;Amp

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Explanation:

5 0
3 years ago
Beyond what point must an object be squeezed for it to become a black hole
mixas84 [53]

Answer:

Schwarzschild radius                                      

Explanation:

A black hole is defined as that object from which light cannot escape form the surface of the object because object is very small an very dense. There are numerous black hole sin the universe.

Black hole is well understood by the concept of "escape velocity". Escape velocity is the speed of any object to break the gravitational pull from another object.

Escape velocity depends on mass of the object and the distance from the center of the object ( how big or small the object is ). If the object is smaller or more denser, than the escape velocity is more. If we squeeze our earth to a radius of about 9 mm sphere, then the escape velocity of any object becomes equal to the velocity of light.

And the radius of any object which have an escape velocity which is same as the velocity of light is known as the  'Schwarzschild radius'.

Any object which is smaller than the "Schwarzschild radius' has an escape velocity more than the speed of light and is termed as a black hole.

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3 0
3 years ago
Part D
seropon [69]

Answer:

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3 0
3 years ago
2. A 15 kg mass fastened to the end of a steel wire of un-
Flauer [41]

Explanation:

Elongation of the wire is:

ΔL = F L₀ / (E A)

where F is the force,

L₀ is the initial length,

E is Young's modulus,

and A is the cross sectional area.

ΔL = T (0.5 m) / ((2.0×10¹¹ Pa) (0.02 cm²) (1 m / 100 cm)²)

ΔL = T (1.25×10⁻⁶ m/N)

T = (80,000 N/m) ΔL

Draw a free body diagram of the mass at the bottom of the circle.  There are two forces: tension force T pulling up and weight force mg pulling down.

Sum of forces in the centripetal direction:

∑F = ma

T − mg = mv²/r

T − mg = mω²r

T − (15 kg) (9.8 m/s²) = (15 kg) (2 rev/s × 2π rad/rev)² (0.5 m + ΔL)

T − 147 N = (2368.7 N/m) (0.5 m + ΔL)

Substitute:

(80,000 N/m) ΔL − 147 N = (2368.7 N/m) (0.5 m + ΔL)

(80,000 N/m) ΔL − 147 N = 1184.35 N + (2368.7 N/m) ΔL

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ΔL = 1.67 mm

6 0
4 years ago
If a car is traveling at an average speed of 60 kilometers per hour how long does it take to travel 12 kilometers
lara31 [8.8K]

Answer:

The time taken to travel is, t = 12 minutes

Explanation:

Given data,

The speed of the car, v = 60 km/h

The distance of travel, d = 12 km

The time taken for the travel is t = ?

The speed is defined as the distance divided by the time taken to travel. The formula for speed is,

                                  v = d/t

∴                                  t = d/v

                                    t = 12 km / 60 km/h

                                    t = 0.2 h

                                     t = 12 minutes

Hence, the time taken to travel is, t = 12 minutes.

5 0
3 years ago
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