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3 years ago

Does anyone know how to do this?

Mathematics

1 answer:

Vlad1618 [11]3 years ago

8 0

Answer:i think you have to equal them to each other

Step-by-step explanation:

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9² • (1+4) + 7 – 3 • 4 =

Marizza181 [45]

The answer is your looking for is 400

5 0

2 years ago

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Question 10: If the product of all the numbers from 1 to 100 is divisible by 2^n, then what is the maximum possible value for n:

Klio2033 [76]

Answer: D

Step-by-step explanation:

100!=2*3*4*...*100

Counting which numbers are divisible by 2:

2,4,6,8,10,12,14,...,96,98,100 : 50 numbers (100/2=50)

Counting which numbers are divisible by 4=2²:

4,8,12,16,20,...96,100: 25 numbers (100/4=25)

Counting which numbers are divisible by 8=2³:

8,16,24,32,40,...,96: 12 numbers (100/8=12.5 ==> 12)

Counting which numbers are divisible by 16=2⁴:

16,32,48,...,96: 6 numbers (100/16=6.25 ==> 6)

Counting which numbers are divisible by 32=2⁵:

32,64,96 : 3 numbers(100/32=3.125 ==>3)

Counting which numbers are divisible by 64=2⁶:

64 : 1 number (100/64=1.5625 ==>1)

Sum of those numbers= 50+25+12+6+3+1=97

100! is divisible by 2⁹⁷.

Answer D

4 0

2 years ago

Read 2 more answers

Can someone please help me.

Katena32 [7]

Given
- f(n) values for n=1,2,3,4
- possible candidates for the function

Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.

N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]

N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]

Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]

Solution: f(n)=4(3^(n-1))

6 0

3 years ago

Gavin had $5460.40 that he divided into tow bank accounts. he deposited 3/8 into a savings account. he deposited the rest into h

Ipatiy [6.2K]

(5460.4)(3/8) = 2,047.65 to savings

5460.4 - 2,047.65 = 3,412.75 checking

4 0

3 years ago

There are 5 red marbles, 2 Green marbles and 3 black marbles. What is the probability that red or black is chosen?(answer in dec

ANEK [815]

Answer:

Step-by-step explanation:

5 red marbles, 2 Green marbles and 3 black marbles = 10 marbles

P (red or black) = number of red or black/ total

= (5+3)/10

=8/10

decimal form = .8

5 0

3 years ago

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