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Fofino [41]
3 years ago
11

Does anyone know how to do this?

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0

Answer:i think you have to equal them to each other

Step-by-step explanation:

You might be interested in
12p + 7 > 139 greater or less than
bazaltina [42]

Answer:

\Huge \boxed{p>11}

Step-by-step explanation:

First, subtract by 7 both sides of equation.

\displaystyle 12p+7-7>139-7

Solve.

\displaystyle 139-7=132

12p>132

Then, divide by 12 both sides of equation.

\displaystyle \frac{12p}{12}=\frac{132}{12}

Solve to find the answer.

\displaystyle 132\div12=11

\huge \boxed{p>11}, which is our answer.

3 0
3 years ago
Could someone please list all of the basic derivative rules?
olchik [2.2K]

Answer:

The sum rule is f' + g'

The difference rule is f' − g'

The product rule is f g' + f' g

The quotient rule is (f' g − g' f )/g2



5 0
3 years ago
Finish the following table for the given function
bogdanovich [222]
It there a picture because if there is u can’t see the picture sorry
6 0
3 years ago
Let A = R−{0}, the set of all nonzero real numbers, and consider the following relations on A × A. Decide in each case whether R
andre [41]

Answer:

Step-by-step explanation:

Let A = R−{0}, the set of all nonzero real numbers, and consider the following relations on A × A.

Given that (a,b) R (c,d) if ad=bc

Or (a,b) R (c,d) if determinant

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =0

a) Reflexive:

We have (a,b) R (a,b) because ab-ab =0 Hence reflexive

b) Symmetric

(a,b) R (c,d) gives ad-bc =0

Or da-cb =0 or cb-da =0 Hence (c,d) R(a,b). Hence symmetric

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5 0
3 years ago
It's the 11th day of autumn and the first leaf has fallen! If the number of leaves on the ground is tripling with each passing d
AlekseyPX

Answer: 1,594,323

Step-by-step explanation:

No of leaves which falls daily on the first day = 1

No of days leaves falls = 14 days.

Solution:

No of leaves of day 1

= 1.

No of leaves on day 2

= 1*3

= 3

No of leaves of day 3

= 3*3

= 9

No of leaves of day 4

= 9*3

= 27

No of leaves on day 5

= 27*3

= 81

No of leaves on day 6.

= 81*3

= 243.

No of leaves of day 7

= 243*3

= 729

No of leaves on day 8

= 729 * 3

= 2187

No of leaves on day 9

= 2187 *3

= 6561

No of leaves on day 10

= 6561 * 3

= 19683

No of leaves on day 11

= 19683 * 3

= 59049

No of leaves on day 12

= 59049 *3

= 177147

No of leaves on day 13

= 531441

No of leaves on day 14

= 531441 * 3

= 1,594,323.

The number of leaves that would be on the ground on the 24th day of autumn would be 1,594,323

8 0
3 years ago
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